Java convert from decimal to 8-bit binary

Question

i wrote simple java code to convert from decimal to 8-bit binary: sorry for this stupid question

 1       int dec=1;
 2       String result="";
 3       String reverse = "";
 4       while(dec!=0)
 5           {
 6               result+=dec%2;
 7               dec=dec/2;    
 8           }            
 9       //8-Bit Binary 
 10       System.out.println("dec length is :"+result.length());

// int j=8-result.length(); // for(int i=0;i

 11        for(int i=0;i<(8-result.length());i++)
 12       {
 13            result+=0;
 14            System.out.println("*");
 15       }
 16       System.out.println("8-Bit before reverse:"+result); 
 17       for(int i = result.length() - 1; i >= 0; i--)
 18        {
 19           reverse = reverse + result.charAt(i);
 20        }
 21       System.out.println("8-bit representation:"+reverse);

the result was : dec length is :1 * * * * 8-Bit before reverse:10000 8-bit representation:00001

but when i remove line 13 (result+=0;) the compiler print 7 asterisk(*), what is the reason for that? length of result will update every time

Ookami · Accepted Answer · 2018-02-23 16:34:17Z

1

It is because of the confition of your for loop:

for(int i=0;i<(8-result.length());i++)

And the action in it:

result+=0;

Increasing the length of result makes the result of 8-result.length() smaller (8 - 2 = 6, 8 - 3 = 5 ...), hence the loop being executed less times.

answered Feb 23, 2018 at 16:34

Ookami

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Elliott Frisch · Accepted Answer · 2018-02-23 16:31:20Z

0

Because result is a String. Adding an int zero to a String, like this

result+=0;

invokes the same behavior as

result+=String.valueOf(0);

answered Feb 23, 2018 at 16:31

Elliott Frisch

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1 Comment

Elliott Frisch Over a year ago

@IhabKhaledShhadat it is not work!!!!!!!!!! Take a deep breath. The computer is a very fast idiot, doing exactly what it has been told to do. The fast way get a binary String is Integer.toBinaryString(int); beyond that, I cannot tell what your question is.

Ihab Khaled Shhadat · Accepted Answer · 2018-02-23 16:53:15Z

0

//Decimal to Binary Conversion
            int dec=1;
            String result= "00000000";
            int i=result.length()-1;
            while(dec!=0)
            {
              char a[]=result.toCharArray();
              a[i--]= String.valueOf(dec%2).charAt(0);
              result=new String(a);
              dec=dec/2;  

            }
            System.out.println(result);

answered Feb 23, 2018 at 16:53

Ihab Khaled Shhadat

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