I want to pass students to group , but my code isn't working I only started coding, so could anyone explain how it works
//file Group.h
class Group{
public:
Group(Students *array[] , int size); // pointer. hard to understand
};
//main.cpp
int main() {
int number = 9;
Students students[number];
Group group(students ,number) //build failed. for some reason
return 0;
}
Don't use pointers in C++. And for the love of god, don't use raw new/delete. Use std::vector.
class Group
{
public:
Group(const std::vector<Students>& v); // no pointers, easy to understand and use
};
int main()
{
int size = 9;
std::vector<Students> students(size);
Group group{students};
return 0;
}
Group argument?
class Group
{public:
Group(Students *array[], int size); // This is actually an "array of
// pointers" to Students, not
// an array of Students
};
int main()
{
int number = 9;
Students students[number]; // The size of an array in standard C++ must
// be a constant value. This is a variable
// length array issue, which C++ doesn't support
Group group(students, number); // Build failed for three reasons.
// 1) Because array size wasn't a constant value.
// 2) Because the first constructor argument is the wrong type.
// 3) You're trying to call a constructor which has not been defined
return 0;
}
To get this to work the way you want to there are three changes you need to make:
class Group
{public:
Group(Students array[], int size){} // Now it's an array of Students
// Also note it has squiggly
// brackets after it, that means it
// has a definition
};
int main()
{
const int number = 9; // Array size is now a constant
Students students[number];
Group group(students, number); // Now you can call the constructor because
// it's been defined
return 0;
}
Students *array[] is not an array and redeclaring it as Students array[] won't make it array either. Also use of raw pointers in C++ is not encouraged.
Group(Students *array , int size)orGroup(Students array[] , int size).