Having this input:
myArray = [[32.4, "bla", 1.44, 0.5, 65.8, "abc"],
[654, "ert"]
[9.4, "a", 1.44, "abc"]];
An array of arrays, I want to compute the sum of each sub-array and also ignoring the string values.
I know that for a single array of this type the sum could be computed as:
sum = myArray.filter(n => !isNaN(n)).reduce((m, n) => m + n);
but when I try to use the same method for a matrix the result is 0.
Any suggestions?
You could try to convert the value to a number with an unary plus + or take zero for adding.
var array = [[32.4, "bla", 1.44, 0.5, 65.8, "abc"], [654, "ert"], [9.4, "a", 1.44, "abc"]],
result = array.map(a => a.reduce((s, v) => s + (+v || 0), 0));
console.log(result);You could use map method and inside filter to get array of numbers only and then reduce to get sum for each array.
const myArray = [
[32.4, "bla", 1.44, 0.5, 65.8, "abc"],
[654, "ert"],
[9.4, "a", 1.44, "abc"]
];
const result = myArray.map(arr => {
return arr
.filter(Number)
.reduce((r, e) => r + e)
})
console.log(result)As you're now dealing with an array of arrays, you could apply that same code, but it will have to be within an outer reduce to loop through the outer array:
const sum = myArray.reduce(
(s, arr) => s + arr.filter(n => !isNaN(n)).reduce((m, n) => m + n),
0
);
Live Example:
const myArray = [
[32.4, "bla", 1.44, 0.5, 65.8, "abc"],
[654, "ert"],
[9.4, "a", 1.44, "abc"]
];
const sum = myArray.reduce((s, arr) => s + arr.filter(n => !isNaN(n)).reduce((m, n) => m + n), 0);
console.log(sum);
,at the end of the second line. (It's not a syntax error because it means the subsequent array will be treated as a property accessor. But it's incorrect. :-) )