How can I get param from URL after #?
Example:
http://localhost/addAccount/#code=qwerty
I tried use url = request.path and url.spit('/') but it isn't working becasuse request.path don't read string after # in url.
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3The # is for html ids and therefore client side, I don't think they are sent with requests.T4rk1n– T4rk1n2018-03-01 22:03:57 +00:00Commented Mar 1, 2018 at 22:03
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3 Answers
In a URL, what travels after # is known as hash. In an HTTP request that reaches a server (server side) this data does not travel to the server. Therefore, on the server side, it is not possible to retrieve it (web browsers do not send this data in the HTTP request).
However, on the client side it is possible. In Javascript you could do:
window. location. hash
Comments
dont try to parse urls manually - use the stdlib urllib.parse.urlparse
function (urlparse.urlparse on python2):
from urllib.parse import urlparse # from urlparse import urlparse on py2
scheme = urlparse('http://localhost/addAccount/#code=qwerty')
print(scheme.fragment)
prints out:
code=qwerty
Unfortunately you cannot get from the server-side the fragement of the url (data after the #). AFAIK all browsers wont send the fragement to the server (the fragement can be used only on client side code (e.g. javascript).
Quoting Wikipedia:
When an agent (such as a Web browser) requests a web resource from a Web server, the agent sends the URI to the server, but does not send the fragment. Instead, the agent waits for the server to send the resource, and then the agent processes the resource according to the document type and fragment value.[2]
I had similar thing recently
So I came up with this simple snippet:
from urllib.parse import parse_qs, urlparse
url = "http://localhost/addAccount/#code=qwerty"
fragment = urlparse(url).fragment
value = parse_qs(fragment).get("code")
print(value.pop()) # querty
We had to have "pop" here, as parse_qs returns list by default
