How to separate HTML string into array or dictionary by Swift3?

Question

I got HTML string from API like this:

let a: String = "<a href="https://www.google.com.tw">https://www.google.com.tw </a>"
let b: String = "<a href="myAppName://app/user/aa3b77411825b88b318d77gg">@Tim </a>Hello Tim"
let c: String = "<a href="myAppName://app/user/aa3b77411825b88b318d77gg">@Tim </a><a href="https://www.google.com.tw">https://www.google.com.tw </a>"

let splitedArray1: [String] = a.componentsSeparatedByString("?????") //splited string which is the best 
let splitedArray2: [String] = b.componentsSeparatedByString("?????") //splited string which is the best
let splitedArray3: [String] = c.componentsSeparatedByString("?????") //splited string which is the best

I want to separate link from them and get the data like following

print(splitedArray1) //["https://www.google.com.tw","https://www.google.com.tw"]
print(splitedArray2) //["myAppName://app/user/aa3b77411825b88b318d77gg","@Tim ","Hello Tim"]
print(splitedArray3) //["myAppName://app/user/aa3b77411825b88b318d77gg","@Tim ","https://www.google.com.tw","https://www.google.com.tw "]

Larme · Accepted Answer · 2018-03-07 09:30:10Z

Possible solution: Use NSAttributedString then enumerate on the NSLinkAttributeName, if there isn't, it means there were no link tag, so you just keep the "string", else, you add the link, then the string.

Quickly written in Playground:

let a: String = "<a href=\"https://www.google.com.tw\">https://www.google.com.tw </a>"
let b: String = "<a href=\"myAppName://app/user/aa3b77411825b88b318d77gg\">@Tim </a>Hello Tim"
let c: String = "<a href=\"myAppName://app/user/aa3b77411825b88b318d77gg\">@Tim </a><a href=\"https://www.google.com.tw\">https://www.google.com.tw </a>"

let values:[String] = [a, b, c]



for aHTMLString in values
{
    let attributedString = try! NSAttributedString.init(data: aHTMLString.data(using: .utf8)!,
                                                        options: [.documentType: NSAttributedString.DocumentType.html],
                                                        documentAttributes: nil)
    var retValues = [String]()
    attributedString.enumerateAttribute(.link,
                                        in: NSRange(location: 0, length: attributedString.string.count),
                                        options: [],
                                        using: { (attribute, range, pointerStop) in
                                            if let attribute = attribute as? URL
                                            {
                                                retValues.append(attribute.absoluteString)
                                            }
                                            let subString = (attributedString.string as NSString).substring(with: range)
                                            retValues.append(subString)
    })

    print("*** retValues: \(retValues)")
}

let targetResult1 = ["https://www.google.com.tw","https://www.google.com.tw"]
let targetResult2 = ["myAppName://app/user/aa3b77411825b88b318d77gg","@Tim ","Hello Tim"]
let targetResult3 = ["myAppName://app/user/aa3b77411825b88b318d77gg","@Tim ","https://www.google.com.tw","https://www.google.com.tw "]
print("targetResult1: \(targetResult1)")
print("targetResult2: \(targetResult2)")
print("targetResult3: \(targetResult3)")

Output:

*** retValues: ["https://www.google.com.tw/", "https://www.google.com.tw "]
*** retValues: ["myappname://app/user/aa3b77411825b88b318d77gg", "@Tim ", "Hello Tim"]
*** retValues: ["myappname://app/user/aa3b77411825b88b318d77gg", "@Tim ", "https://www.google.com.tw/", "https://www.google.com.tw "]
targetResult1: ["https://www.google.com.tw", "https://www.google.com.tw"]
targetResult2: ["myAppName://app/user/aa3b77411825b88b318d77gg", "@Tim ", "Hello Tim"]
targetResult3: ["myAppName://app/user/aa3b77411825b88b318d77gg", "@Tim ", "https://www.google.com.tw", "https://www.google.com.tw "]

There are small differences, I copied your "target" (splitArray), and it's missing a space in the last one, and my code tend to add a final "/" on links.

Mahendra · Accepted Answer · 2018-03-07 10:24:07Z

1

I've created this extension to get url.

extension String {
  func getUrl() -> String? {
      let rss = self.split { (char) -> Bool in
          return char == ">"
      }
      if let final = rss.last?.split(separator: "<"), let first = final.first {
          return String(first)
      }
      return nil
  }

  var hrefUrl: String {
    let matchString = "=\""
    let arrComponents = self.components(separatedBy: matchString)
    if let first = arrComponents.last, let str = first.split(separator: "\"").first {

        return String(str)
    }
    return ""
  }
}

Usage:

let a: String = "<a href=\"https://www.google.com.tw\">https://www.google.com.tw </a>"
a.getUrl()  //output: https://www.google.com.tw 

//or

a.hrefUrl //output: https://www.google.com.tw

edited Mar 7, 2018 at 10:24

answered Mar 7, 2018 at 9:34

Mahendra

8,9624 gold badges36 silver badges59 bronze badges

1 Comment

tolerate＿Me_Thx Over a year ago

This is swift4? I use swift3 playgound to test and "let rss = self.split ......." here get an error. String don't have split function.

Bio-Matic · Accepted Answer · 2018-03-07 09:23:55Z

0

Simple solution without libraries - just use String.replaceOccurences(of:... to replace odd strings like a href, a into split parameter (like "|") and then use componentsSeparatedByString("|") to get your components.

answered Mar 7, 2018 at 9:23

Bio-Matic

8231 gold badge9 silver badges20 bronze badges

Comments

Milap Kundalia · Accepted Answer · 2018-03-07 10:21:42Z

0

Use the regular expression for extracting the URL. Below I have written the code snippet.

        let text = "<a href=\"https://www.google.com\">"

        let regex = try! NSRegularExpression(pattern: "<a[^>]+href=\"(.*?)\"[^>]*>")
        let range = NSMakeRange(0, text.characters.count)
        let matches = regex.matches(in: text, range: range)
        for match in matches {
            let strURL = (text as NSString).substring(with: match.rangeAt(1))
            print(strURL)
        }

answered Mar 7, 2018 at 10:21

Milap Kundalia

1,6281 gold badge17 silver badges25 bronze badges

1 Comment

tolerate＿Me_Thx Over a year ago

But my text is <a href=\"google.com.tw\">google.com.tw </a> . And I want to print the array not string

Collectives™ on Stack Overflow

How to separate HTML string into array or dictionary by Swift3?

4 Answers 4

Comments

1 Comment

Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

Comments

1 Comment

Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related