Python sorting using for loop

Question

I have written a for loop to display names in python idle as shown below.

1.SRA-D12-TY2-2017WW22.4.129
2.SRA-D12-TY2-2017WW27.5.168
3.SRA-D12-TY2-2017WW16.5.92
4.SRA-D12-TY2-2017WW20.2.115
5.SRA-D12-TY2-2017WW25.2.149
6.SRA-D12-TY2-2017WW29.5.188
7.SRA-D12-TY2-2017WW36.1.234
8.SRA-D12-TY2-2017WW31.3.201

The code I have written to display the above items is

for i in data.get('files'):
    new_data = i.get('uri').strip('/')
    platform_display = "{}.{}".format(count,new_data)
    platform_dict[count] = new_data 
    count += 1
    print platform_display

I want it to be displayed as

1.SRA-D12-TY2-2017WW36.1.234
2.SRA-D12-TY2-2017WW31.3.201
3.SRA-D12-TY2-2017WW29.5.188

etc in descending order

Please let me know how can I sort the names

If it will always be the same format, try splitting on 'WW' and then parsing the right side as a float and sorting on that — sshashank124
– sshashank124, Commented Mar 14, 2018 at 5:56

Jay Shankar Gupta · Accepted Answer · 2018-03-14 06:06:27Z

4

l1=[
'SRA-D12-TY2-2017WW22.4.129',
'SRA-D12-TY2-2017WW27.5.168',
'SRA-D12-TY2-2017WW16.5.92',
'SRA-D12-TY2-2017WW20.2.115',
'SRA-D12-TY2-2017WW25.2.149',
'SRA-D12-TY2-2017WW29.5.188',
'SRA-D12-TY2-2017WW36.1.234',
'SRA-D12-TY2-2017WW31.3.201'
]
l1=sorted(l1, key=lambda x: x.split("WW")[-1],reverse=True)
for i in l1:
  print(i)

Output:

SRA-D12-TY2-2017WW36.1.234
SRA-D12-TY2-2017WW31.3.201
SRA-D12-TY2-2017WW29.5.188
SRA-D12-TY2-2017WW27.5.168
SRA-D12-TY2-2017WW25.2.149
SRA-D12-TY2-2017WW22.4.129
SRA-D12-TY2-2017WW20.2.115
SRA-D12-TY2-2017WW16.5.92

answered Mar 14, 2018 at 6:06

Jay Shankar Gupta

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3 Comments

Mushif Ali Nawaz Over a year ago

I think x.rsplit("WW") would be more suitable here?

Mushif Ali Nawaz Over a year ago

And in this case whole strings can be compared without splitting. Just like this: sorted(l1, reverse=True)

Jay Shankar Gupta Over a year ago

Thanks for the Suggestion @MushifAliNawaz

Sociopath · Accepted Answer · 2018-03-14 06:11:46Z

0

Just use reversed sort.

Lets say all your item in the list called l,

l=['SRA-D12-TY2-2017WW22.4.129',
 'SRA-D12-TY2-2017WW27.5.168',
 'SRA-D12-TY2-2017WW16.5.92',
 'SRA-D12-TY2-2017WW20.2.115',
 'SRA-D12-TY2-2017WW25.2.149',
 'SRA-D12-TY2-2017WW29.5.188',
 'SRA-D12-TY2-2017WW36.1.234',
 'SRA-D12-TY2-2017WW31.3.201']

sorted(l, reverse=True)

edited Mar 14, 2018 at 6:11

Sociopath

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answered Mar 14, 2018 at 6:03

Bilash Amantay

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1 Comment

Sravani Chinta Over a year ago

Thank you so much it is working i am able to sort the list

Vimanyu · Accepted Answer · 2018-03-14 06:13:23Z

0

Try this:

from operator import itemgetter

platform_list = []
for i in data.get('files'):
    new_data = i.get('uri').strip('/')
    platform_list.append([new_data.split("WW")[-1],new_data])

first_item = itemgetter(0)
new_list = sorted(platform_list, key = first_item)
counter = 0
for i in new_list:
    counter += 1
    print "%d.%s" %(counter,i[1])

answered Mar 14, 2018 at 6:13

Vimanyu

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