How to find through JSON array which has nested object elements

Question

Below is my JSON array and I want to find if contact array has specific value or not.

 data =  [ { _id: 5a67294923aba20014e2fe5a,
            customerLocation: '473 Victoria St, Singapore 198371',
            customerName: 'UNIVERSAL',
            id: 'UNI3L2',
            customerType: 'customer',
            contact:
             [ 'Brian spilak',
               'Brian spilak2',
               'Brian spilak3',
               'Brian spilak4',
               'Brian spilak5' ] } ];

JAVASCRIPT

function findContact(data,con){
           return data.contact.find(item => {
            return item.data.contact == con;
        })
     }    

    console.log('Contact Name :', findContact(data,'Brian spilak2'));

It's not clear what you are trying to find. Will data have more than one customer object? Are you trying to find a particular customer? Or will it always just have one object? — Mark
– Mark, Commented Mar 14, 2018 at 6:07
@Mark_M No there will be only one customer object and one contact object. I want to find if contact object has specific value or not. — Breana James
– Breana James, Commented Mar 14, 2018 at 6:08

guijob · Accepted Answer · 2018-03-14 06:11:21Z

2

item doesn't have data.contact property and your data response it an array, so you have to specify an index do work with:

function findContact(data,con){
           return data[0].contact.find(item => {
            return item == con;
        })
     }

edited Mar 14, 2018 at 6:11

answered Mar 14, 2018 at 6:09

guijob

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1 Comment

Mark Over a year ago

data is an array. It has no contact property.

Praveen Kumar Tripathi · Accepted Answer · 2018-03-14 06:04:15Z

0

You can use data.contact for contact data shown

answered Mar 14, 2018 at 6:04

Praveen Kumar Tripathi

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Comments

Hassan Imam · Accepted Answer · 2018-03-14 06:20:11Z

0

You can use array#find with array#includes to check if a name exists in the contact property of the object.

var data = [ { _id: '5a67294923aba20014e2fe5a', customerLocation: '473 Victoria St, Singapore 198371', customerName: 'UNIVERSAL', id: 'UNI3L2', customerType: 'customer', contact: [ 'Brian spilak', 'Brian spilak2', 'Brian spilak3', 'Brian spilak4', 'Brian spilak5'] } ];
var result = data.find(o => o.contact.includes('Brian spilak2'));
console.log(result);

edited Mar 14, 2018 at 6:20

answered Mar 14, 2018 at 6:07

Hassan Imam

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4 Comments

Mark Over a year ago

Why are you using some() rather than just the returned boolean from includes()?

Hassan Imam Over a year ago

Some is used here to iterate the array.

Breana James Over a year ago

@HassanImam What if i want to return found object ?

Hassan Imam Over a year ago

I have updated the solution to return the complete object.

Abinash Gupta · Accepted Answer · 2018-03-14 06:21:32Z

0

This one returns all the objects matching the name criteria in the array.

function filterName(data, srchName) {
   return data.filter((obj) => {
        return obj.contact.indexOf(srchName) !== -1
    })
}

console.log(filterName(data, 'Brian spilak'));

answered Mar 14, 2018 at 6:21

Abinash Gupta

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Comments

brk · Accepted Answer · 2018-03-14 06:05:41Z

-1

Use indexOf.Since it is only one object data[0] is used to get the first object, if it is an array of object you can use forEach method

var data = [{
  _id: '5a67294923aba20014e2fe5a',
  customerLocation: '473 Victoria St, Singapore 198371',
  customerName: 'UNIVERSAL',
  id: 'UNI3L2',
  customerType: 'customer',
  contact: ['Brian spilak',
    'Brian spilak2',
    'Brian spilak3',
    'Brian spilak4',
    'Brian spilak5'
  ]
}];

function findContact(data, con) {
  if (data[0].contact.indexOf(con) !== -1) {
    return 'found';
  } else {
    return 'not found';
  }

}

console.log('Contact Name :', findContact(data, 'Brian spilak2'));

answered Mar 14, 2018 at 6:05

brk

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