Order objects in array based on values of two attributes

Question

I have an array of N objects and each object has the following fields:

{
  id: 'an id',
  description: 'a description',
  isUser: true/false
}

I need to order that array based on two things:

Firstly, if the description includes either 'dog', 'cat' or 'animal', it should have sooner position in the array. Secondly, if the value isUser is false, it should also have a sooner position in the array.

I have notice that the sort function doesn't help when you want to prioritize by value of different attributes, so I am wondering what is the best way to do this in Javascript (or Lodash, which I am also using: https://lodash.com/)

What do you mean by sooner position? do you want object with properties isUser: false and description: 'dog'/'cat' or 'animal' to appear before the rest other elements ? — Vikramaditya
– Vikramaditya, Commented Mar 14, 2018 at 13:49

Nina Scholz · Accepted Answer · 2018-03-14 13:56:02Z

1

You could check if the wanted top string are in the description and move these item to top, as well as false values of isUser.

var array = [{ id: 1, description: 'cat', isUser: false }, { id: 5, description: 'dog', isUser: true }, { id: 6, description: 'flower', isUser: true }, { id: 7, description: 'cat', isUser: true }, { id: 2, description: 'animal', isUser: false }, { id: 3, description: 'tree', isUser: false }, { id: 4, description: 'dog', isUser: false }];
		
array.sort(function (a, b) {
    var top = ['dog', 'cat', 'animal'];
    return top.includes(b.description) - top.includes(a.description) || a.isUser - b.isUser;
});

console.log(array);

.as-console-wrapper { max-height: 100% !important; top: 0; }

answered Mar 14, 2018 at 13:56

Nina Scholz

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1 Comment

Hommer Smith Over a year ago

Nina one question, why in the includes case you put B description first, and when doing the isUser you put the A first? So, why not do: return top.includes(b.description) - top.includes(a.description) || b.isUser - a.isUser;?

Luis felipe De jesus Munoz · Accepted Answer · 2018-03-14 13:56:56Z

1

var test = [{
  id: 'an id',
  description: 'a description dog',
  isUser: false
},{
  id: 'an id 2',
  description: 'a description animal',
  isUser: true
},{
  id: 'an id 3',
  description: 'a description',
  isUser: true
},{
  id: 'an id 4',
  description: 'a description',
  isUser: false
}]

function sort(arr){
  return arr.sort(a=> !(a.description.includes('dog')||a.description.includes('cat')||a.description.includes('animal') || !a.isUser))
}

console.log(sort(test))

answered Mar 14, 2018 at 13:56

Luis felipe De jesus Munoz

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Comments

Vikramaditya · Accepted Answer · 2018-03-14 13:59:37Z

0

Assuming you question is to rearrange the existing array based on the properties and conditions given.

// grouping on basis of "description" 

const animalGrp = _.groupBy(array, (t) => _.includes(t.description, 'dog') || _.includes(t.description, 'cat') || _.includes(t.description, 'animal') );

// grouping on basis of "isUser" 
const userGrp = _.groupBy(animalGrp.false, 'isUser');

// final output
const result = [...animalGrp.true, ...userGrp.true, ...userGrp.false]

answered Mar 14, 2018 at 13:59

Vikramaditya

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Comments

ccesare · Accepted Answer · 2018-03-14 14:01:36Z

0

You can pass a compareFunction to sort method of array, so the sort function should help. Example:

yourArray.sort( function(a, b) {
    if ( !a.isUser || a.description == 'animal')  return -1;
    return 1;
});

edited Mar 14, 2018 at 14:01

answered Mar 14, 2018 at 13:47

ccesare

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