I want to return the key of the object where it's ContractID value equals 10. So in this example I want to return 0.
{
0 : {ContractID: 10, Name: "dog"}
1 : {ContractID: 20, Name: "bar"}
2 : {ContractID: 30, Name: "foo"}
}
I've tried using the filter method but it doesn't work how I'd have wanted.
var id = objname.filter(p => p.ContractID == 10);
This instead returns the array, not the key. How can I return the key?
Use find on the Object.keys()
let obj = {
'0' : {ContractID: 10, Name: "dog"},
'1' : {ContractID: 20, Name: "bar"},
'2' : {ContractID: 30, Name: "foo"}
}
let res = Object.keys(obj).find(e => obj[e].ContractID === 10);
console.log(res);However, your "object" looks more like it should be an array. Either create it directly correct as an array, or convert it to one first. Then use findIndex()
let obj = {
'0' : {ContractID: 10, Name: "dog"},
'1' : {ContractID: 20, Name: "bar"},
'2' : {ContractID: 30, Name: "foo"}
};
obj.length = Object.keys(obj).length;
let arr = Array.from(obj);
let key = arr.findIndex(e => e.ContractID === 10);
console.log(key);You could simply use a for in loop :
var o = {
0 : {ContractID: 10, Name: "dog"},
1 : {ContractID: 20, Name: "bar"},
2 : {ContractID: 30, Name: "foo"}
};
var k;
for(key in o){
if(o[key].ContractID == 10){
k = key;
break;
}
}
console.log(k);
const keys = Object.keys(objname).filter(key => objname[key].ContractId === 10)