Can`t take value from html textarea to php variable

Question

I made a blogging platform and I have an ajax updated page where I can select which article to display and his comments and add comments. When I leave a comment it takes the logged user info, the article on which the comment has been made but the comment value is not taken to store it in the database. This is the code :

<div align="center">
  <h3>Comentarii:</h3>
  <form method="POST">
    <textarea rows="4" cols="50" name="comentariu" placeholder="Comenteaza">
        </textarea><br>
    <input type="submit" name="submit"><br>
    <hr>
  </form>
</div>

<?php
  $comnou = $_POST['comentariu'];
  $comuser = $_SESSION['user'];
  $conadaugacom = mysqli_connect("localhost", "root", "", "blog");
  $sqladaugacom = "insert into comentarii (continut_comentarii, 
  user_comentarii, articol_comentarii) values ('$comnou', '$comuser', '$ta')";
  mysqli_query($conadaugacom, $sqladaugacom);
  mysqli_close($conadaugacom);
?>

AJAX Code ->

function showUser(str) {
  if (str == "") {
    document.getElementById("txtHint").innerHTML = "";
    return;
  } else {
    if (window.XMLHttpRequest) {
      xmlhttp = new XMLHttpRequest();
    } else {
      xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
    }
    xmlhttp.onreadystatechange = function() {
      if (this.readyState == 4 && this.status == 200) {
        document.getElementById("txtHint").innerHTML = this.responseText;
      }
    };
    xmlhttp.open("GET", "getuser.php?q=" + str, true);
    xmlhttp.send();
  }
}

is $ta defined elsewhere? This is wide open to sql injection btw — Professor Abronsius
– Professor Abronsius, Commented Mar 17, 2018 at 18:42

mplungjan · Accepted Answer · 2018-03-18 06:31:52Z

1

Make sure that before POST request serialize the data from form.

html

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<div align="center">
  <h3>Comentarii:</h3>
  <form method="POST">
    <textarea rows="4" cols="50" name="comentariu" placeholder="Comenteaza">
        </textarea><br>
    <input type="submit" name="submit"><br>
    <hr>
  </form>
</div>

Jquery

<script>
     $('input').submit(function(e){
        e.preventDefault();

        var data = $('form').serialize();
        $.ajax({
           url: 'your_url_to_post.php',
           data: data,
           success: function(response){

           },
           type: 'POST'
        });
     });
</script>

php file

add this line to check comentariu not empty

if(isset($_POST['comentariu'])){
     $comentariu = $_POST['comentariu];
}

edited Mar 18, 2018 at 6:31

mplungjan

180k29 gold badges183 silver badges246 bronze badges

answered Mar 17, 2018 at 18:45

akhil

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6 Comments

mplungjan Over a year ago

Please answer a few questions until you have the 50 rep needed to comment. This is not an answer.

akhil Over a year ago

i know i am new here

mplungjan Over a year ago

NOW it’s an answer

mplungjan Over a year ago

You however assume jQuery

Chris Over a year ago

This does not provide an answer to the question. Once you have sufficient reputation you will be able to comment on any post; instead, provide answers that don't require clarification from the asker. - From Review

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