filter an array of nested objects in 5 level

Question

I am trying filter this array with .filter.

var objList = [
  {
    "name": "Object0Name",
    "id": "Object0ID",
    "Object1List": [
      {
        "id": "Object1id_A1",
        "name": "Object1Name_A1",
        "Object2List": [
          {
            "id": 187,
            "name": "Object2Name_A1",
            "Object3List": [
              {
                "id": "mammal",
                "name": "mammal",
                "Object4List": [
                  {
                    "id_client": "rabbit",                   
                    "Currency": "EUR"  
                  },
                  {
                    "id_client": "cat",                    
                    "Currency": "EUR",
                  },
                  {
                    "id_client": "tiger",
                    "Currency": "EUR",                    
                  }
                ]
              }
            ]
          }
        ]
      },
      {
        "id": "Object1id_B1",
        "name": "Object1Name_B1",
        "Object2List": [
          {
            "id": 189,
            "name": "Object2Name_B1",
            "Object3List": [
              {
                "id": "fish",
                "name": "fish",
                "Object4List": [
                  {
                    "id_client": "tiger shark",                   
                    "Currency": "EUR",
                    
                  },
                  {
                    "id_client": "tuna",
                    "currency": "GBP",                   
                  },
                  
                ]
              }
            ]
          }
        ]
      }
    ]
  }
]

var response= objList.filter(function(Object0List){
			return Object0List.Object1List.filter(function(Object1List){
				return	 Object1List.Object2List.filter(function(Object2List){
					return	 Object2List.Object3List.filter(function(Object3List){
						return	 Object3List.Object4List.filter(function(Object4List){
							return Object4List.id_client==="tiger shark";

						});
					});
				});
			});
		});



var myJSON = JSON.stringify(response);
console.log('The animal is:');
console.log(myJSON);

But the filter doesn't work. I am receiving all objects. I must receive: [ { "name": "Object0Name", "id": "Object0ID", "Object1List": [

  {
    "id": "Object1id_B1",
    "name": "Object1Name_B1",
    "Object2List": [
      {
        "id": 189,
        "name": "Object2Name_B1",
        "Object3List": [
          {
            "id": "fish",
            "name": "fish",
            "Object4List": [
              {
                "id_client": "tiger shark",                   
                "Currency": "EUR",

              }                 

            ]
          }
        ]
      }
    ]
  }
]

} ]

Could someone help me find out what I'm doing wrong? I'm sure the problem is that I'm using the .filter function badly but it took several hours and I'm not capable of fixing it. I think that I do not understand this function for nested objects, I tried to filter the array of nested objects with lambda expressions but I'm also not able.

Thanks you very much.

What do you want to get? All objects that contain the searched word and their parents? — Jonas Wilms
– Jonas Wilms, Commented Mar 18, 2018 at 20:17
And why do you name the keys "Object1List", "Object2List" instead of just children ? — Jonas Wilms
– Jonas Wilms, Commented Mar 18, 2018 at 20:20
Hi Jonas W and Artur. Yes, I want to get all the objects that contain the searched word and their parents — bulbasurmsr
– bulbasurmsr, Commented Mar 18, 2018 at 20:33
Hi Jonas, I don't know. Call it as you want, it would also be valid children1list and children2list — bulbasurmsr
– bulbasurmsr, Commented Mar 18, 2018 at 20:36

Nina Scholz · Accepted Answer · 2018-03-18 21:19:36Z

1

You could check each property which is an array and take only filtered values.

This approach mutates the original array.

function filter(array, value) {
    var temp = array.filter(o =>
        Object.keys(o).some(k => {
            var t = filter(Array.isArray(o[k]) ? o[k] : [], value);
            if (o[k] === value) {
                return true;
            }
            if (t && Array.isArray(t) && t.length) {
                o[k] = t;
                return true;
            }
        })
    );
    if (temp.length) {
        return temp;
    }
}

var array = [{ name: "Object0Name", id: "Object0ID", Object1List: [{ id: "Object1id_A1", name: "Object1Name_A1", Object2List: [{ id: 187, name: "Object2Name_A1", Object3List: [{ id: "mammal", name: "mammal", Object4List: [{ id: "rabbit", Currency: "EUR" }, { id: "cat", Currency: "EUR" }, { id: "tiger", Currency: "EUR" }] }] }] }, { id: "Object1id_B1", name: "Object1Name_B1", Object2List: [{ id: 189, name: "Object2Name_B1", Object3List: [{ id: "fish", name: "fish", Object4List: [{ id: "tiger shark", Currency: "EUR" }, { id: "tuna", currency: "GBP" }] }] }] }] }],
    result = filter(array, 'tiger shark');

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

edited Mar 18, 2018 at 21:19

answered Mar 18, 2018 at 21:06

Nina Scholz

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1 Comment

bulbasurmsr Over a year ago

Hi Nina, your function is valid, thank you very much.

Jonas Wilms · Accepted Answer · 2018-03-18 20:53:02Z

0

I assume that every of your objects has this structure:

  {
   id: "sth",
   name: "whatever"
   children: [ /***/ ]
  }

So then it is quite easy to filter recursively:

 function filter(arr, search){
   const result = [];
   for(const {name, id, children} of arr){
     children = filter(children, search);
     if(children.length || id === search)
       result.push({id, name, children });
   }
   return result;
 }

Usable as:

  var response = filter(objList, "tiger shark");

answered Mar 18, 2018 at 20:53

Jonas Wilms

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1 Comment

bulbasurmsr Over a year ago

Thank you very much for your response, but the name of the id is not the same, so it can not be recursive. In the example I'm wrong and I name all identical ids, I've changed it now (In the Object4List the id is name id_client now) I am so sorry by the mistake

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