Find difference in array only using key using lodash

Question

How can I find all values in an array A - where the key is not in array B ( a bit like a SQL Not In ) . I don't want to compare the whole array , just one property - but I do want to return all fields for the differences using lodash ( or simpler )

const arrayA = [
  { sku:"1", name:"one"},
  { sku:"2", name:"two"}
]
const arrayB = [
  { sku:"1", name:"One Product"},
  { sku:"2", name:"Two Product"},
  { sku:"3", name:"Three Product"}
]

The results should be :

{ sku:"3", name:"Three Product"}

Thank you for your time.

Henry Tseng · Accepted Answer · 2018-03-19 19:21:16Z

1

You could also use:

const arrayA = [
  { sku:"1", name:"one"},
  { sku:"2", name:"two"}
];
const arrayB = [
  { sku:"1", name:"One Product"},
  { sku:"2", name:"Two Product"},
  { sku:"3", name:"Three Product"}
];

let diff = _.differenceWith(arrayB, arrayA, (a, b) => _.isEqual(a.sku, b.sku) );

edited Mar 19, 2018 at 19:21

answered Mar 19, 2018 at 18:58

Henry Tseng

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nem035 · Accepted Answer · 2018-03-19 19:19:45Z

0

You don't really need lodash for this. What you need is to filter the second array and eliminate all elements existing in the first array.

const arrayA = [
  { sku:"1", name:"one"},
  { sku:"2", name:"two"}
]
const arrayB = [
  { sku:"1", name:"One Product"},
  { sku:"2", name:"Two Product"},
  { sku:"3", name:"Three Product"}
]

console.log(
  // filter B such that we only leave items from B that are not in A
  arrayB.filter(b => 
    !arrayA.some(a => a.sku === b.sku)
  )
)

edited Mar 19, 2018 at 19:19

answered Mar 19, 2018 at 16:54

nem035

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