Getting each element of a list and mapping it to a struct in elixir

Question

How would you take a list of strings, eg.

["jeff", "bezos", "21"]

and map that to a struct

%{:fistname => "jeff", :lastname => "bezos", :age => "21"}

Is it possible to use the Enum functions or would you use the map functions. I need this struct in the specified format so that I can then send it to a database

leifg · Accepted Answer · 2018-03-20 01:07:21Z

4

I assume the strings are in the same order every time?

Then you can just pattern match:

[firstname, lastname, age] = array
%{:fistname => firstname, :lastname => lastname, :age => age}

If the list contains more than 3 elements:

[firstname, lastname, age | _] = array
%{:fistname => firstname, :lastname => lastname, :age => age}

answered Mar 20, 2018 at 1:07

leifg

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5 Comments

Errol Hassall Over a year ago

Thanks very much. So all the data comnes from a csv file, but I only need the first 5 for one struct and then the rest go into another struct would this work say if I did option 2, took the first 3 then did a similar thing but took the 7 after the first 3? or would it have to be done another way?

Errol Hassall Over a year ago

maybe something like {,,_, other_fields...} = array

leifg Over a year ago

well you can do [firstname, lastname, age | rest] = array

leifg Over a year ago

all the additional fields will be in rest which is also a list

Errol Hassall Over a year ago

O right and then you call rest and do the same thing again??

Dogbert · Accepted Answer · 2018-03-20 03:46:58Z

4

You can zip the list of keys with your list of values and then pass that to Map.new/1:

iex(1)> Enum.zip([:firstname, :lastname, :age], ["jeff", "bezos", "21"]) |> Map.new
%{age: "21", firstname: "jeff", lastname: "bezos"}

answered Mar 20, 2018 at 3:46

Dogbert

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