How to loop a json keys result from bash script

Question

input.json:-

{
"menu": {
  "id": "file",
  "value": "File",
  "user": {
    "address": "USA",
    "email": "[email protected]"
  }
}
}

Command:-

result=$(cat input.json | jq -r '.menu | keys[]')

Result:-

id
value
user

Loop through result:-

for type in "${result[@]}"
do
    echo "--$type--"
done

Output:-

--id
value
user--

I want to do process the keys values in a loop. When I do the above, It result as a single string.

How can I do a loop with json keys result in bash script?

using bash is redundant in such case

RomanPerekhrest
– RomanPerekhrest

2018-03-20 12:45:21 +00:00
Commented Mar 20, 2018 at 12:45 — RomanPerekhrest
– RomanPerekhrest, Commented Mar 20, 2018 at 12:45

Paul Bismuth · Accepted Answer · 2020-05-09 23:12:24Z

8

The canonical way :

file='input.json'
cat "$file" | jq -r '.menu | keys[]' | 
while IFS= read -r value; do
    echo "$value"
done

bash faq #1

But you seems to want an array, so the syntax is (missing parentheses) :

file='input.json'

result=( $(cat "$file" | jq -r '.menu | keys[]') )

for type in "${result[@]}"; do
    echo "--$type--"
done

Output:

--id--
--value--
--user--

edited May 9, 2020 at 23:12

Paul Bismuth

32 bronze badges

answered Mar 20, 2018 at 11:28

Gilles Quénot

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5 Comments

Galet Over a year ago

I am getting jq: error: syntax error, unexpected IDENT, expecting $end (Unix shell quoting issues?) at <top-level>, line 1: when executing second approach.

Galet Over a year ago

Still I get error in this line result=( $(jq -r '.menu | keys[]' input.json) ) after your updation. Also I want input.json name to be dynamic

Galet Over a year ago

result=( $(cat input.json | jq -r '.menu | keys[]') ). this works.

Gilles Quénot Over a year ago

You need to install it (no deps)

Nicolas Henneaux Over a year ago

Thanks, the only solution actually working for my case !

RomanPerekhrest · Accepted Answer · 2018-03-20 12:51:07Z

2

Using bash to just print an object keys from JSON data is redundant.
Jq is able to handle it by itself. Use the following simple jq solution:

jq -r '.menu | keys_unsorted[] | "--"+ . +"--"' input.json

The output:

--id--
--value--
--user--

edited Mar 20, 2018 at 12:51

answered Mar 20, 2018 at 12:44

RomanPerekhrest

93.1k4 gold badges75 silver badges112 bronze badges

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