Parsing XML in C# from stream

Question

I've tried several methods, from Linq to loading the data to an XML document, but i can't seem to be able to return the result that i need.

here's the example XML:

<serv:message xmlns:serv="http://www.webex.com/schemas/2002/06/service" xmlns:com="http://www.webex.com/schemas/2002/06/common" xmlns:event="http://www.webex.com/schemas/2002/06/service/event"><serv:header><serv:response><serv:result>SUCCESS</serv:result><serv:gsbStatus>PRIMARY</serv:gsbStatus></serv:response></serv:header><serv:body><serv:bodyContent xsi:type="event:createEventResponse" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"><event:sessionKey>11111111</event:sessionKey><event:guestToken>111111111111111111111</event:guestToken></serv:bodyContent></serv:body></serv:message>

And, here's what i've tried to do:

StreamReader reader = new StreamReader(dataStream);
XmlDocument doc = new XmlDocument();
doc.LoadXml(reader.ReadToEnd());
XmlNamespaceManager ns = new XmlNamespaceManager(doc.NameTable);
XmlNamespaceManager ns2 = new XmlNamespaceManager(doc.NameTable);
XmlNamespaceManager ns3 = new XmlNamespaceManager(doc.NameTable);
ns.AddNamespace("serv", "http://www.webex.com/schemas/2002/06/service");
ns2.AddNamespace("com", "http://www.webex.com/schemas/2002/06/common");
ns3.AddNamespace("event", "http://www.webex.com/schemas/2002/06/service/event");
XmlNode node = doc.SelectSingleNode("result",ns);

Yet, for some reason i cannot ever seem to return the actual result, which should be either 'SUCCESS' or 'FAILURE' based on the actual xml above.

How can i do this?

Steve B · Accepted Answer · 2011-02-08 23:24:18Z

2

your xpath query is not correct.

try this one :

XmlNode node = doc.SelectSingleNode("//serv:result",ns);

or

XmlNode node = doc.SelectSingleNode("serv:message/serv:header/serv:response/serv:result",ns);

answered Feb 8, 2011 at 23:24

Steve B

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4 Comments

Phillip Over a year ago

Thank you, the 2nd one worked for me, however when i do node["serv:result"].Value.ToString() it doesn't seem to want to return the actual result. Should i be doing this with Innertext to return the result?

Phillip Over a year ago

It gives a A first chance exception of type 'System.NullReferenceException' occurred in WeBeX Demo.exe System.NullReferenceException: Object reference not set to an instance of an object.

Steve B Over a year ago

decompose you code in smaller parts... something is null. It's hard to tell with so few code

Phillip Over a year ago

Here's the code i used: XmlNode node = doc.SelectSingleNode("serv:message/serv:header/serv:response/serv:result",ns); if (node != null) { Console.WriteLine("not null"); Console.WriteLine(node.Value.ToString()); } else { Console.WriteLine("null"); } It returns: not null A first chance exception of type 'System.NullReferenceException' occurred in WeBeX Demo.exe System.NullReferenceException: Object reference not set to an instance of an object.

BrokenGlass · Accepted Answer · 2011-02-08 23:24:24Z

0

This works:

XDocument doc = XDocument.Load(@"test.xml");
XNamespace serv = "http://www.webex.com/schemas/2002/06/service";
var result = doc.Descendants(serv + "result").First().Value;

answered Feb 8, 2011 at 23:24

BrokenGlass

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3 Comments

Phillip Over a year ago

when trying to write 'var' to the command line, i get an error with your code there: A first chance exception of type 'System.ArgumentException' occurred in mscorlib.dll System.ArgumentException: Illegal characters in path. Tried changing it to a string as well, but same result.

BrokenGlass Over a year ago

I tested this code with your XML as input and it works perfectly, result is actually of type string, you can use it as such, i.e. Console.WriteLine(result)

Phillip Over a year ago

i see what i did wrong. I used XDocument.Load() instead of XDocument.Parse() considering i was using it from a stream reader. Works great, returned exactly what i needed! Thank you so much!

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