In python3 I have some bytes. I want to export them to C source code. Outside python I use "xxd -i binary_file" command.
Example:
x = b'abc123'
print(bytes_to_c_arr(x))
# should output:
unsigned char x[] = { 0x61, 0x62, 0x63, 0x31, 0x32, 0x33 };
Is there ready method or handy one-liner? I can do away without type declaration, only bytes for contents would suffice.
1. print([hex(i) for in x])
2. print(a.hex())
Results will be:
1. ['0x61', '0x62', '0x63', '0x31', '0x32', '0x33']
2. '616263313233'
In case you want to use caps or not:
def bytes_to_c_arr(data, lowercase=True):
return [format(b, '#04x' if lowercase else '#04X') for b in data]
x = b'abc123'
print("unsigned char x[] = {{{}}}".format(", ".join(bytes_to_c_arr(x))))
print("unsigned char x[] = {{{}}}".format(", ".join(bytes_to_c_arr(x, False))))
# output: unsigned char x[] = {0x61, 0x62, 0x63, 0x31, 0x32, 0x33}
# unsigned char x[] = {0X61, 0X62, 0X63, 0X31, 0X32, 0X33}
Here is a very fast way (134 MiB/s on Intel i7-8700, Python 2) that avoids iterating using slow, interpreted Python loops and iterates in optimized code
import binascii
x=b'abc123'
hex=binascii.b2a_hex(x)
# add \x prefix
hex2=bytearray(4*len(b))
hex2[0::4]='\\'*len(b)
hex2[1::4]='x'*len(b)
hex2[2::4]=hex[0::2]
hex2[3::4]=hex[1::2]
Using your example, this will generate these hex literals
\x61\x62\x63\x31\x32\x33
Just put this inside a double quoted string. I've omitted that code for brevity.
