loop json with no array php [duplicate]

Question

I have json like below, how can i loop each id

{
    "id1": {
        "AreaN": "\u30ef\u30fc\u30eb\u30c9\u30d0\u30b6\u30fc\u30eb",
        "AreaM": "\uff9c\uff70\uff99\uff84\uff9e\uff8a\uff9e\uff7b\uff9e\uff70\uff99"
    },
    "id2": {
        "AreaN": "\u30ef\u30fc\u30eb\u30c9\u30d0\u30b6\u30fc\u30eb",
        "AreaM": "\uff9c\uff70\uff99\uff84\uff9e\uff8a\uff9e\uff7b\uff9e\uff70\uff99"
    }
}

I tried but it does not get all the ids, i cant change the json.

$json = json_decode($doc);
if( count($json) > 0 )
{
    foreach($json as $area)
    {

    }
}

In my case the ids i want to get are not inside an array. Is it possible to loop the ids and keep them as objects, i prefer object access than using square brackets.

Your code looks correct. What is it that you are trying to achieve in your foreach? — Avi_B
– Avi_B, Commented Mar 26, 2018 at 4:25
it seems my code was correct there was an error somewhere else should i delete this question? — tsukimi
– tsukimi, Commented Mar 26, 2018 at 6:12
@tsukimi I think probably you're using PHP7.2 and above, and stdClass is not implementing Countable interface. Refer here: php.net/manual/en/… So to fix this, you just change to assoc array, i.e. json_decode($doc, 1) — Js Lim
– Js Lim, Commented Mar 26, 2018 at 6:26

Js Lim · Accepted Answer · 2018-03-26 04:24:20Z

2

$json = json_decode($doc, 1);
foreach ($json as $id => $area) {
    // $id is "id1", "id2"
    // $area is AreaN & AreaM
}

the 2nd param for json_decode if true will return as array, otherwise will be object

answered Mar 26, 2018 at 4:24

Js Lim

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