Why no reference is created for function f
if ( function f() { } ) {
console.log( typeof f );
}
// result: undefined Whereas assigning/setting variable works fine inside if( )
if ( f = 'assigned' ) {
console.log( typeof f );
}
// result: stringI need to know that whats going on in the first case as the second case is working as expected
Can anybody explain, please?
Since you have put function f() { } in expression context, it is a named function expression and not a function declaration.
That means that while it creates a function, and that function has the name f, it creates the variable with the name f in the scope of the function (itself) and not in the scope in which the function is created.
// Global scope
function a() {
// a is a function declaration and creates a variable called a to which the function is assigned in the scope (global) that the declaration appears in
function b() {
// b is a function declaration and creates a variable called a to which the function is assigned in the scope (function a) that the declaration appears in
}
var c = function d() {
// c is a variable in the scope of the function b. The function d is assigned to it explicitly
// d is a function expression and creates a variable called d to which the function is assigned in the scope (function d) of itself
};
}
fisfunction f() { }fis undefined when usingvar g = function f () {}. stackoverflow.com/questions/336859/…