-2

There are two arrays:

a1 = [0, 2, 4, 6, 8];
a2 = [1, 3, 5, 7, 9];

How I get this:

a = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9];

I wanna to use RxJs or else.

If the value isn‘t a number, like an Object.

 a1 = [A, C, E, G, I]; 
 a1 = [{'name': 'Lucy'}, {'name': 'Lily'}, {'name': 'Jerry'}, {'name': 'Tom'}, {'name': 'Smith'}]

 a2 = [B, D, F, H, J]; 
 a2 = [{'name': 'Jack'}, {'name': 'John'}, {'name': 'Anan'}, {'name': 'Bob'}, {'name': 'Dav'}]

 a = [A, B, C, D, E, F, G, H, I, J];
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9
  • a1.concat(a2) Commented Mar 31, 2018 at 13:17
  • 1
    a1.concat(a2).sort() actually Commented Mar 31, 2018 at 13:17
  • a1.concat(a2).sort(); Commented Mar 31, 2018 at 13:18
  • WHile I was typing... ;) Commented Mar 31, 2018 at 13:18
  • 1
    Why you vote -1? Commented Mar 31, 2018 at 13:28

3 Answers 3

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1 
[...a1,...a2].sort((a,b) => a-b)

That's ES6 syntax.

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1 Comment

How should that work with objects ?!?
0

With concat() and sort()

a1 = [0, 2, 4, 6, 8];
a2 = [1, 3, 5, 7, 9];

a = a1.concat(a2).sort();

console.log(a)

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3 Comments

How should that work with objects?!
He edited its question. Never talked about objects before
I just used number for a example....
0 
  const result = [];

  for(var i = 0; i < arr1.length && i < arr2.length; i++)
    result.push(arr1[i], arr2[i]);

  result push(...arr1.slice(i), ...arr2.slice(i));

That merges two arrays (arr1, arr2) by taking one each.

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