Remove FILL from string in JavaScript

Question

How would I remove specific, yet slightly random text from a string in JavaScript?

EG:

a string var string = "!warn <@123456789123456789> I eat apples for breakfast"; The !warn will always be at the start. <@ will always be at the start of the numbers. > will always be at the end of the numbers. The <@****> numbers are random and are never the same. The length of the <@****> can range between 18-20 numbers.

I want to end up with the string I eat apples for breakfast.

Thanks!

Have you tried anything? I'd suggest using RegEx.

Nielsvh
– Nielsvh

2018-04-02 23:06:38 +00:00
Commented Apr 2, 2018 at 23:06 — Nielsvh
– Nielsvh, Commented Apr 2, 2018 at 23:06

Ele · Accepted Answer · 2018-04-02 23:25:27Z

3

An alternative is using regex

Explanation: https://regex101.com/r/SLhRMA/1

var str = "!warn <@123456789123456789> I eat apples for breakfast";

console.log(str.replace(/!warn <@\d+>\s?/, ''))

edited Apr 2, 2018 at 23:25

answered Apr 2, 2018 at 23:00

Ele

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4 Comments

Sphinx Over a year ago

My thought is console.log(str.replace(/(?:\!warn \<@\d+\>)(.*?)/, '$1'))

Ele Over a year ago

@Sphinx your approach is beautiful!

Simon R Over a year ago

@Sphinx You'd probably want to trim that once making the replacement. Good approach though.

Sphinx Over a year ago

@SimonR, Yes, but that is not a big problem. I am thinking if the string is very large, which method will be more efficiency.

Simon R · Accepted Answer · 2018-04-02 23:23:03Z

1

var text = "!warn <@123456789123456789> I eat apples for breakfast";

console.log(text.replace(/^\!warn <@.*?>\s?/,""));

How this works is it replaces the text based on the pattern provided (/\!warn <@.*?>\s?/s).

The first part is a literal check that it says !warn at the very beginning of the string (we escape the explanation point because that has a pattern meaning). Then we're checking for <@ and then any characters between the @ and >. We're using a non-greedy check - so it'll match up to the first >. Then we're checking for one single space so it makes the very first part of the bit you want as the first character.

An explaination of this is available on Regex101

edited Apr 2, 2018 at 23:23

answered Apr 2, 2018 at 23:10

Simon R

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