I have a json
{
"field" : [
{
"value" : 1.0
},
{
"value" : 2.0
}
]
}
How do I get a List[String] that are of values List(1.0, 2.0) ?
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2 Answers
Personally I would do it like:
import io.circe.generic.auto._
import io.circe.parser.decode
case class ValueWrapper(value: Double)
case class Result(field: Seq[ValueWrapper])
decode[Result](jsonString).map(_.field.map(_.toString)).getOrElse(Seq.empty)
Actually, you could do that without Decoder derivation. Basically it means that you do not use most often used part of Circe, and instead rely on Circe optics. I guess it would be sth like (I haven't tested it!):
import io.circe.optics.JsonPath._
root.field.value.double.getAll(jsonString).map(_.toString)
Comments
Circe optics is the most concise way to do that.
import io.circe.optics.JsonPath._
import io.circe.parser._
val json = parse(jsonStr).right.get // TODO: handle parse errors
root.field.each.value.double.getAll(json) // == List(1.0, 2.0)
