PhpStorm live template variable default value - directory of file

Question

I've created live template that uses variables, something like :

A::set($CATEGORY$,$MESSAGE$);

And I want to set default value of variable $CATEGORY$ as a directory, where the file I've used this live template located. There is expression fileName() that does a thing close to my task.

So if I use my live template in file located app\views\home\index.php - I would like to get default value for $CATEGORY$ - 'home'. How can I do this?

From one of the 2017.x version PhpStorm supports GroovyScript in Live Templates -- you can code such extraction of home from the value returned by fileName() function yourself (there is no built-in Live Template function to do that). You may check youtrack.jetbrains.com/issue/IDEA-155907#comment=27-2662765 for some info. — LazyOne
– LazyOne, Commented Apr 4, 2018 at 9:03

user8620109 · Accepted Answer · 2018-04-04 14:11:34Z

1

I've made it using GroovyScript as LazyOne says. Didn't found what value live template function groovyScript() will output, but my code doing what i wanted.

Solution:

String path = _editor.getVirtualFile().getPath();
Integer lastIndex = path.lastIndexOf('/');
Integer startIndex = path.substring(0,lastIndex).lastIndexOf('/')+1;
path.substring(startIndex,lastIndex);

answered Apr 4, 2018 at 14:11

user8620109

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1 Comment

Scott Anderson Over a year ago

I have followed the references from LazyOne's answer, but if I wanted to make a script which I call by file name, how do I pass the filePath() as a parameter and receive it in the script? I assume I would call the script with groovyScript("~/my_file", filePath())

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