I would like to know how to get all the value of a specific information. In this case, I want to get all the 'name' of a message and convert it in an array. Example of message:
"xxxxxxxxxx name:yyyy; xxxxxxxxxxxxxxxxxxx name:yyyyy;"
Code (I only got the first 'name'):
for i in range(0,len(message)):
start = message.find('name') + 4
end = message.find(';', start)
a=message[start:end]
split=a.split(';')
print(split)
Using regex:
import re
s = "xxxxxxxxxx name:yyyy; xxxxxxxxxxxxxxxxxxx name:yyyyy;"
print(re.findall(r"name:[a-zA-Z]+", s))
Output:
['name:yyyy', 'name:yyyyy']
r"(?<=name:).*?(?=;)", and in case the region boundaries are also relevant, better use finditer to get the full groups.If you want to use str.find, you should provide a starting position for start, like you did for end, e.g. the previous end or 0 in the first iteration. Then, continue until start is -1, i.e. not found.
end = 0
while True:
start = message.find('name', end)
if start == -1:
break
end = message.find(';', start)
a = message[start + 5 : end]
print(start, end, repr(a))
Or you could split the message at whitespaces and use a conditional list comprehension:
>>> [s[5:-1] for s in message.split() if s.startswith("name")]
['yyyy', 'yyyyy']
In practice, however, I would recommend using regular expressions as shown in the other answer.
Your logic almost works, you can change it to:
message = "xxxxxxxxxx name:yyyy; xxxxxxxxxxxxxxxxxxx name:zzzzzz;"
start = message.find('name') # find first start
stop = message.find(';', start) # find first stop after first start
names = [] # all your found values get appended into this
while -1 < start < stop: # ensure start is found and stop is after it
names.append(message[start+5:stop]) # add 5 start-pos to skip 'name:' and slice value
# from message and put into names
start = message.find('name',stop) # find next start after this match
if start == -1: # if none found, you are done
stop = -1
else:
stop = message.find(';', start) # else find the end for this start
if start != -1: # if your last ; is missing, the while above will find
# start but no stop, in that case add all from last start pos to end
names.append(message[start:])
print ( names)
Output:
['yyyy', 'zzzzzz']
def formatFunction(x):
index_of_name = x.index('name')
if index_of_name >= 0:
return x[index_of_name:]
else:
return None
message_list = message.split(';')
message_list = message_list.map(formatFunction)
formated_list = [x for x in message_list if x]
print(formated_list)
