How to run background process with bash -c [duplicate]

Question

I have a command to start background process

./daemon.sh &

it works okay but when i try to run it the following way

bash -i -c "./daemon.sh & ; ./another_daemon.sh &"

it throws the exception bash: syntax error near unexpected token `;'

Is there any way to start background process(es) with bash -i -c "..."

Petr Skocik · Accepted Answer · 2018-04-04 21:07:15Z

6

It's not a -c issue.

You need to lose the ; after the &. The shell syntax doesn't accept a semicolon in conjunction with an ampersand. Either of the following is acceptable

bash -i -c "... ; ..."
bash -i -c "... & ..."

but bash -i -c "... & ; ..." is invalid.

edited Apr 4, 2018 at 21:07

answered Apr 4, 2018 at 10:50

Petr Skocik

60.6k7 gold badges105 silver badges165 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Yury Bondarau Over a year ago

without ampersand, it works. for instance command bash -i -c "./daemon.sh ; ./another_daemon.sh " runs with no issues

chepner Over a year ago

Ampersands and semicolons are both command terminators; using both implies the semicolon terminates an empty command, and bash's syntax doesn't allow empty commands. ./daemon.sh & ./another_daemon & is sufficient.

Collectives™ on Stack Overflow

How to run background process with bash -c [duplicate]

1 Answer 1

2 Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Linked

Related