Javascript console.log() returns a reference error to a php string

Question

I am trying to output the array values into the console but I get an undefined error:

ERROR

ReferenceError: Ciencia is not defined

CODE

 $sql = "SELECT topic FROM book_list WHERE topic != '' ORDER BY topic ASC";
        $result = mysqli_query($db, $sql);
        <?php 
            while($topic = mysqli_fetch_assoc($result)){?>
                console.log(<?php echo $topic['topic']; ?>);
        <?php }?>

If I output the sql in the mysql console I get this

+-------------+
| topic       |
+-------------+
| Ciencia     |
| Comedia     |
| Comedia     |
| Matematicas |
| Science     |
+-------------+

Thanks!

Read the generated source and you'll see your problem

SLaks
– SLaks

2018-04-04 18:11:36 +00:00
Commented Apr 4, 2018 at 18:11 — SLaks
– SLaks, Commented Apr 4, 2018 at 18:11

Scott Marcus · Accepted Answer · 2018-04-04 18:14:25Z

2

Seems like it's trying console.log(Ciencia) instead of console.log("Ciencia").

Change your line to:

console.log("<?php echo $topic['topic']; ?>");

answered Apr 4, 2018 at 18:14

Scott Marcus

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Comments

Barmar · Accepted Answer · 2018-04-04 18:30:46Z

0

You need to convert the PHP string to a Javascript string, rather than trying to use the PHP string itself as an expression. json_encode() is good for this.

console.log(<?php echo json_encode($topic['topic']); ?>);

This is better than just putting quotes around the echo statement, in case the PHP variable contains special characters that need to be encoded (e.g. quotes).

answered Apr 4, 2018 at 18:30

Barmar

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