I'm having trouble with this logic. I'm trying to find a way where a single variable will have multiple values without using array. Here is my code
var num = {
from: 500,
to: 700
};
if (num == 500 && num == 600 && num==700) {
console.log("working");
}
else {
console.log("not working")
}
You could take a function for checking the range.
function check({ from, to }, value) {
return from <= value && value <= to;
}
var num = { from: 100, to: 300 };
if (check(num, 500) && check(num, 600) && check(num, 700)) {
console.log("working");
} else {
console.log("not working")
}
console.log(check(num, 200));Use a function and try comparing the values.
var num = {
from: 100,
to: 300,
checkValue:function(num){
return this.from <= num && num <= this.to
}
};
console.log('1st check');
if (num.checkValue(100) && num.checkValue(600) && num.checkValue(700)) {
console.log("working");
}
else {
console.log("not working")
}
console.log('2nd check');
if (num.checkValue(120) && num.checkValue(150) && num.checkValue(250)) {
console.log("working");
}
else {
console.log("not working")
}
from and to in num object.To access your object (Variables with multiple values) you have to do like this :
var num = {
from: 100,
to: 300
}
console.log(num.from); //This will print 100
console.log(num.to); //This will print 300
and you can do this
num.from += 1;
console.log(num.from); //This will print 101
So your (Ryan Arellano) code must be like this :
function check(num, value) {
return num.from <= value && value <= num.to;
}
var num = { from: 100, to: 300 };
if (check(num, 500) && check(num, 600) && check(num, 700)) {
console.log("working");
} else {
console.log("not working")
}
console.log(check(num, 200));
