PHP use array to require php files

Question

I have saw this answer about require multiple php files, I want to do it use class,like this

class Core
{
    function loadClass($files)
    {
        $this->files = func_get_args();
        foreach($files as $file) {
            require dirname(__FILE__)."/source/class/$file";
        }
    }
}

But when I use

$load = new Core;
$load->loadClass('class_template.php');

it doesn't work, can anyone help me to find the error ?

because you are reading $files as array and sending it as a string. just add one new line under loadClass file. if(!is_array($files)){ $files = array($files)} or when you are calling your files pass it in array like. $load->loadClass(['class_template.php']) — Ashish Patel
– Ashish Patel, Commented Apr 7, 2018 at 5:07
I would recommend looking into PSR0 or PSR4 auto loading of classes. — ArtisticPhoenix
– ArtisticPhoenix, Commented Apr 7, 2018 at 5:10
@AshishPatel thanks,now I know how different array between class and pure function — carry0987
– carry0987, Commented Apr 7, 2018 at 5:28
@ArtisticPhoenix I know that,but I just want to require 5 or 6 class files,so I decide make an require function file — carry0987
– carry0987, Commented Apr 7, 2018 at 5:29

Aniket Sahrawat · Accepted Answer · 2018-04-07 05:08:58Z

1

You should pass $this->files to foreach. $files is a local variable and a string. $this->files is a instance variable and an array.

class Core {
    function loadClass() { // there is no need for `$files` here
        $this->files = func_get_args();
        foreach($this->files as $file) { // $this->files not $files
            require dirname(__FILE__)."/source/class/$file";
        }
    }
}

$load = new Core;
$load->loadClass('class_template.php');

answered Apr 7, 2018 at 5:08

Aniket Sahrawat

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1 Comment

carry0987 Over a year ago

I will try it,wait for a moment

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