Python Selenium Webdriver element found but can not click on it

Question

Goal is to click on a checkbox on login page. I find the element by XPATH, but can't click on it.

>>> elem = driver.find_element_by_xpath("//input[@type='checkbox'][@name='conditions']")
>>> elem.is_displayed()
False
>>> elem.is_enabled()
True
>>> elem.get_attribute('outerHTML')
u'<input type="checkbox" class="custom-control-input" name="conditions">'

When I try elem.click(), exception occurs: selenium.common.exceptions.ElementNotVisibleException: Message: element not visible but element is clearly visible, since the page is loaded and I work from terminal.

Other error when I use different selector is: driver.find_element_by_xpath('/html/body/div[2]/main/section/div/div[3]/div/div[1]/form/p[1]/label/input').click()

selenium.common.exceptions.WebDriverException: Message: unknown error: Element <input type="checkbox" class="custom-control-input" name="conditions"> is not clickable at point (51, 549). Other element would receive the click: <span class="custom-control-description font-weight-regular">...</span>

I tried with injecting JavaScript but didn't work. driver.execute_script("arguments[0].style.visibility = 'visible';",elem)

Any ideas how to work around this?

try to explicit wait for the visibility of element then click on it. — cruisepandey
– cruisepandey, Commented Apr 12, 2018 at 12:35

undetected Selenium · Accepted Answer · 2018-04-12 15:48:24Z

2

As per your code trials when you try :

elem.click()

You are seeing :

selenium.common.exceptions.ElementNotVisibleException: Message: element not visible

Which means the desired element is still not visible in the HTML DOM

Even before trying to click when you are try :

elem.is_displayed()

You are seeing :

False

But when you try :

elem.is_enabled()

You are seeing :

True

So combining all these observations it can be either of the situations :

Element is present in the DOM but still not visible/interactable. In this case you need to induce WebDriverWait and then invoke click() as follows :
```
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//input[@type='checkbox' and @name='conditions']"))).click()
```
Element is present in the DOM but not within the Viewport. In this case you need to invoke execute_script() to bring the element within the Viewport and then invoke click() as follows :
```
elem = driver.find_element_by_xpath("//input[@type='checkbox' and @name='conditions']")
driver.execute_script("arguments[0].scrollIntoView(true);", elem)
elem.click()
```
There is a possibility that the Locator Strategy you have adapted is not unique and identifies multiple WebElements and the first element to be identified may be hidden. In this case is_displayed() will always return False and you have to construct a unique Locator Strategy which identifies the intended element uniquely.

There is a possibility that the style attribute of the element is set to display: none; and in that case you have to use execute_script() method as follows :

elem = driver.find_element_by_xpath("//input[@type='checkbox' and @name='conditions']")
driver.execute_script("arguments[0].removeAttribute('style')", elem)
elem.click()

edited Apr 12, 2018 at 15:48

answered Apr 12, 2018 at 15:37

undetected Selenium

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1 Comment

brada Over a year ago

Thanks @DebanjanB great answer, I tried and double checked all of it, but always get the error: Element ... is not clickable at point ...

selenium.common.exceptions.WebDriverException: Message: unknown error: Element <input type="checkbox" class="custom-control-input" name="conditions"> is not clickable at point (51, 286). Other element would receive the click: <span class="custom-control-description font-weight-regular">...</span>

Ankur Singh · Accepted Answer · 2018-04-12 12:26:31Z

0

You can use this XPATH :- //input[@type='checkbox'and @name='conditions']

For below error:- Use wait before click event

selenium.common.exceptions.WebDriverException: Message: unknown error: Element is not clickable at point (51, 549). Other element would receive the click: ...

answered Apr 12, 2018 at 12:26

Ankur Singh

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