Passing a string to a bash script via an argument

Question

I'm writing a bash script that, amongst other things, triggers a git commit on a codebase for a specified Drupal 6 site. The script accepts two arguments, the second of which is the commit message for the git commit.

#!/bin/sh

directoryName=${1}
commitMsg=${2}

echo $directoryName
echo $commitMsg

git add .
git commit -vam "The commit message"

The script is called like this:

sh git-bash-test.sh name_of_directory "Custom commit message"

How can I change out "The commit message" for the value stored in $commitMsg?

The answer seems too obvious to be what you're really asking; "git commit -vam "${commitMsg}""? Am I missing something? — gamen
– gamen, Commented Feb 13, 2011 at 14:27

Rami C · Accepted Answer · 2011-02-13 14:39:37Z

4

Simply replace it with "$commitMsg":

git commit -vam "$commitMsg"

answered Feb 13, 2011 at 14:39

Rami C

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Comments

Eugene Yarmash · Accepted Answer · 2011-02-13 14:37:19Z

1

sh git-bash-test.sh name_of_directory "$commitMsg"

Note the double-quotes around $commitMsg.

answered Feb 13, 2011 at 14:37

Eugene Yarmash

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