How would one go about using php include() with GET paramters on the end of the included path?
IE:
include("/home/site/public_html/script.php?id=5");
4 Answers
How would one go about using php include() with GET paramters on the end of the included path?
You could write into $_GET:
$_GET["id"] = 5; // Don't do this at home!
include(".....");
but that feels kludgy and wrong. If at all possible, make the included file accept normal variables:
$id = 5;
include("....."); // included file handles `$id`
1 Comment
Jacob
Might be even tidier to have a function or class in the included file, and pass the required variables as arguments to the function/constructor.
You don't, include loads files via the local filesystem.
2 Comments
Marc B
Unless the specified path is a url, in which case an 'http://' type path WOULD be requested via http, but that's highly ugly and incredibly insecure.
ocodo
yes, it's possible, but oh so horrible. (If "URL fopen wrappers" are enabled in PHP, you can do it, you can also make me projectile-vomit this way too.)
If you really wanted to, you could just do this, which would have the same result.
<?php
$_GET['id'] = 5;
include "/home/site/public_html/script.php";
?>
but then you might as well just define the variable and include it
<?php
$id = 5;
include "/home/site/public_html/script.php";
?>
and reference the variable as $id inside script.php.
Comments
Well you could use:
include("http://localhost/include/that/thing.php?id=554&y=16");
But that's very seldomly useful.
It might be possible to write a stream wrapper for that, so it becomes possible for local scripts too.
include("withvars:./include/that/thing.php?id=554");
I'm not aware if such a solution exists yet.
includereads the file form the file system and does not initiate a HTTP request.script.phpit will be able to read the existing$_GETin the calling script.