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?a=1&b=2&c=3
I only want to change b=6 while keep the other things the same, how to do it?
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Do you want to change URL variable??Manish Trivedi– Manish Trivedi2011-02-14 06:06:49 +00:00Commented Feb 14, 2011 at 6:06
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6 Answers
Following function if you have to replace any b=XXX with b=newBValue
function ReplaceB(strQuery,newBValue)
{
var idxStart= strQuery.indexOf("b=")
if(idxStart<0)
return; // b= not found, nothing to change
var idxFin=strQuery.substr(0,idxStart).indexOf("&");
var newQuery;
if(idxFin<0)
newQuery = strQuery.substr(0,idxStart) + "b="+newBValue
else
newQuery = strQuery.substr(0,idxStart) + "b="+newBValue+strQuery.substr(idxStart+idxFin)
return newQuery;
}
Comments
here a small function to do this:
jQuery.replaceURLParam = function (oldURL, replaceParam, newVal) {
var iStart = oldURL .indexOf(replaceParam + '=');
var iEnd = oldURL .substring(iStart + 1).indexOf('&');
var sEnd = oldURL .substring(iStart + iEnd + 1);
var sStart = oldURL .substring(0, iStart);
var newURl = sStart + replaceParam + '=' + newVal;
if (iEnd > 0) {
newURl += sEnd;
}
return newURl;
}
document.body.innerHTML = jQuery.replaceURLParam('www.foo.com?a=1&b=2&c=3', 'b', 6) ;
Comments
var queryStr = "?a=1&b=2&c=3";
var startTag = "b=";
var endTag = "&";
var index1 = queryStr.indexOf(startTag) + startTag.length;
var index2 = queryStr.indexOf(endTag,index1);
var newValue = 23;
queryStr = queryStr.substr(0, index1) + newValue + queryStr.substr(index2);
alert(queryStr);
See it here : http://jsfiddle.net/aQL8p/
Comments
var test = "?a=1&b=2&c=3".replace(/b=2/gi,"b=6");
alert(test);
Example
var test = "?a=1&b=2&c=3".replace("b=2","b=6");
alert(test);
Example
var test = "?a=1&b=2&c=3".split("b=2").join("b=6");
alert(test);
Example
Regardless of Number
Want to change to value of b regardless of number it is already? Use:
var test = "?a=1&b=2&c=3".replace(/b=\d/gi, "b=6");
alert(test);
Example
var queryString = '?a=1&b=2&c=3'.replace(/([?&;])b=2([$&;])/g, '$1b=6$2');
(JavaScript regex does not support lookbehinds).
2 Comments
See if this works for you - a more or less universal urlFor:
https://gist.github.com/4108452
You would simply do
newUrl = urlFor(oldUrl, {b:6});
