json_encode empty with no error [duplicate]

Question

I got an object. I need to turn into JSON for storage but when I try to encode it into JSON it returns an empty JSON object. When I tried to use json_last_error.

The code I used

echo $payload["sub"];
echo json_encode($user);
echo json_last_error_msg();

The result I get

"102573480781696194937{}No error".

The User class I'm trying to encode

<?php
    /**
     * Created by PhpStorm.
     * User: Student
     * Date: 13-4-2018
     * Time: 10:40
     */

    namespace php;
    class User
    {
        private $isAdmin = false;
        private $registeredFood = array();
        private $googleID;
        private $name;
        private $notes = array();
        private $email;

        /**
         * User constructor.
         * @param $googleID
         */
        public function __construct($googleID)
        {
            $this->googleID = $googleID;

        }


        /**
         * @return mixed
         */
        public function getGoogleID()
        {
            return $this->googleID;
        }

        /**
         * @return bool
         */
        public function isAdmin()
        {
            return $this->isAdmin;
        }

        /**
         * @param bool $isAdmin
         */
        public function setIsAdmin($isAdmin)
        {
            $this->isAdmin = $isAdmin;
        }

        /**
         * @return array
         */
        public function getRegisteredFood()
        {
            return $this->registeredFood;
        }

        /**
         * @param array $registeredFood
         */
        public function setRegisteredFood($registeredFood)
        {
            $this->registeredFood = $registeredFood;
        }

        /**
         * @return mixed
         */
        public function getName()
        {
            return $this->name;
        }

        /**
         * @param mixed $name
         */
        public function setName($name)
        {
            $this->name = $name;
        }

        /**
         * @return array
         */
        public function getNotes()
        {
            return $this->notes;
        }

        /**
         * @param array $notes
         */
        public function setNotes($notes)
        {
            $this->notes = $notes;
        }

        /**
         * @return mixed
         */
        public function getEmail()
        {
            return $this->email;
        }

        /**
         * @param mixed $email
         */
        public function setEmail($email)
        {
            $this->email = $email;
        }
    }
?>

I hope someone can help me

JSON is meant for encoding data and will not work on classes or bits of code. I am not sure what contents you have in variable $user. — Carsten Massmann
– Carsten Massmann, Commented Apr 18, 2018 at 7:30
What do you expect it to encode? All properties are private. — M. Eriksson
– M. Eriksson, Commented Apr 18, 2018 at 7:30
stackoverflow.com/questions/9896254/php-class-instance-to-json — deEr.
– deEr., Commented Apr 18, 2018 at 7:31
I would recommend you to look at PHP's JsonSerializable interface if you want complete control over the encoded json object. — M. Eriksson
– M. Eriksson, Commented Apr 18, 2018 at 7:32

sensorario · Accepted Answer · 2018-04-18 07:51:54Z

4

It is because your class's properties are private.

An example class with only private properties ...

php > class Foo { private $bar = 42; }
php > $obj = new Foo();

do not expose values:

php > echo json_encode($obj);
{}

But an example class with public properties ...

php > class Bar { public $foo = 42; }
php > $objBar = new Bar();

do it!

php > echo json_encode($objBar);
{"foo":42}

\JsonSerializable

PHP provide an'interafce \JsonSerializable that require a method jsonSerialize. This method is automatically called by json_encode().

class JsonClass implements JsonSerialize {
    private $bar;
    public function __construct($bar) {
        $this->bar = $bar;
    }
    public function jsonSerialize() {
        return [
            'foo' => $this->bar,
        ];
    }
}

I prefer this solution because is not good to expose publicly properties

serialization and unserialization ...

If you need to serialize and unserialize php object you can ...

php > class Classe { public $pub = "bar"; }
php > $obj = new Classe();
php > $serialized = serialize($obj);
php > $original = unserialize($serialized);
php > var_dump($original);
php shell code:1:
class Classe#2 (1) {
  public $pub =>
  string(3) "bar"
}

$serialized variable contains O:6:"Classe":1:{s:3:"pub";s:3:"bar";}. As you can see is not a json, but is a format that allow you to recreate original object using unserialize function.

edited Apr 18, 2018 at 7:51

answered Apr 18, 2018 at 7:32

sensorario

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6 Comments

M. Eriksson Over a year ago

Gah! I was just about to post an answer using the JsonSerializable interface. You beat me to the punch :-p I totally agree though. JsonSerializable is the cleanest approach.

Lars Dormans Over a year ago

Is there a JsonDeserializable interface to revert the encoding back to object?

M. Eriksson Over a year ago

@LarsDormans - No. When it's converted to JSON, it's simply a JSON object. JSON is a simple notation for presenting data, it doesn't have any concept of functions or similar. It's no longer your class.

sensorario Over a year ago

No, but you can $serialized = serialize($obj) and unserialize with $original = unserialize($serialized). An object serialized is quite different from json but it allow you to send objects via http requests ^_^

M. Eriksson Over a year ago

Just a heads up on serialize(). That creates a serialized version of your class, but it isn't a "general" notation. It's PHP-specific, so if you want to be able to use that data in some other language, you would need to create a parser for it yourself.

|

csb · Accepted Answer · 2018-04-18 07:37:37Z

0

You have a couple of options here.

Option 1: Make your class properties public

Like what sensorario mentioned, change the visibility of your properties so that it is accessible from outside the class, which is where you are calling json_encode.

Option 2: Introduce a method/function within the class to return the encoded JSON object

Have a toJson() function inside your User class.

Of course, there are way more options - such as extending User so that User is not "contaminated", etc.

But yup, the general problem is your private properties.

answered Apr 18, 2018 at 7:37

csb

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