Create dataframe column name or list element with a variable [duplicate]

Question

To create a data.frame or a list I can write

data.frame(yo=1:2, wesh=3:4)

  yo wesh
1  1    3
2  2    4

list(yo=1:2, wesh=3:4)

$yo
[1] 1 2

$wesh
[1] 3 4

But if I write

i <- "yo"
data.frame(i=1:2, wesh=3:4)

   i wesh
1  1    3
2  2    4

list(i=1:2, wesh=3:4)
$i
[1] 1 2

$wesh
[1] 3 4

The i doesn't update to "yo" in the output. How to make it possible?

x <- data.frame(i=1:2, wesh=3:4) i <- "yo" library(data.table) setnames(x, old=c("i"), new=c("yo")) — Sorif Hossain
– Sorif Hossain, Commented Apr 19, 2018 at 10:16

Sotos · Accepted Answer · 2018-04-19 10:00:06Z

2

The reason is because It is not evaluated when you define it as the name of the variable in data.frame(). Try data.frame(i = i, wesh = 3:4) to see the difference. However, a workaround can be to use setNames, i.e.

setNames(data.frame(1:2, 3:4), c(i, 'wesh'))

#same for lists
#setNames(list(1:2, 3:4), c(i, 'wesh'))

which gives,

   yo wesh
1  1    3
2  2    4

answered Apr 19, 2018 at 10:00

Sotos

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