XML output generating using XSLT

Question

I have an XML source file as an input which is the following:

<?xml version="1.0" encoding="UTF-8"?>
<catalog>
  <car>
    <brand>Mercedes</brand>
    <type>ClassA</type>
    <engine>Diesel</engine>
    <seats>5</seats>    
  </car>

  <car>
    <brand>Audi</brand>
    <type>A8</type>
    <engine>Diesel</engine>
    <seats>2</seats>    
  </car>

  <car>
    <brand>Mercedes</brand>
    <type>ClassB</type>
    <engine>Petrol</engine>
    <seats>5</seats>
  </car>
</catalog>

I need to filter the cars using an .xsl styleshett (XSLT) according to various data (for example: I want the list of the Mercedes brand cars with all of it's properties). My output file's structure (XML tags) has to be the same as the input after the filter.

In this case (filter Mercedes brand cars) the output has to be:

<?xml version="1.0" encoding="UTF-8"?>
<catalog>
  <car>
     <brand>Mercedes</brand>
     <type>ClassA</type>
     <engine>Diesel</engine>
     <seats>5</seats>    
  </car>

  <car>
    <brand>Mercedes</brand>
    <type>ClassB</type>
    <engine>Petrol</engine>
    <seats>5</seats>
  </car>
</catalog>

zx485 · Accepted Answer · 2018-04-19 14:59:36Z

1

You can simply filter out any non-Mercedes brand cars with

<xsl:template match="car[brand!='Mercedes']" />

Combine this with the identity template to copy all remaining nodes:

<xsl:template match="@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()" />
    </xsl:copy>
</xsl:template>

You can reverse the approach by explicitly excluding certain brands (here 'Audi' and 'Ford') and keeping all the others with

<xsl:template match="car[brand='Audi' or brand='Ford']" />

answered Apr 19, 2018 at 14:59

zx485

29.1k28 gold badges55 silver badges65 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Daniel Haley Over a year ago

+1 It's also good to note that car[brand!='Mercedes'] only filters out cars that have a brand element. To also filter out cars that don't have a brand element use car[not(brand='Mercedes')] instead. Also, if using XSLT 2.0+, you can write car[brand='Audi' or brand='Ford'] as car[brand=('Audi','Ford')].

imran · Accepted Answer · 2018-04-20 06:40:27Z

0

<xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>


    <xsl:template match="catalog">
        <xsl:element name="catalog">
            <xsl:for-each select="//car">
                <xsl:choose>
                    <xsl:when test=".[brand='Audi']"/>
                    <xsl:otherwise>
                        <xsl:copy-of select="."/>
                    </xsl:otherwise>
                </xsl:choose>
            </xsl:for-each>
        </xsl:element>
    </xsl:template>

answered Apr 20, 2018 at 6:40

imran

4614 silver badges8 bronze badges

Collectives™ on Stack Overflow

XML output generating using XSLT

2 Answers 2

1 Comment

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

Comments

Your Answer

Sign up or log in

Post as a guest

Related