Zend_Controller_Router_Route_Regex allow '?' in pattern

Question

Imagine situation, when the url should looks like

where page param is optional.

Of course, custom route should be defined. Consider the following code:

    $route = new Zend_Controller_Router_Route_Regex(
        'catalog/([-a-z]+)(?:\?page=([0-9]*))?',
        array('controller'=>'catalog','action'=>'list','page'=>''),
        array(1=>'section',2=>'page'),
        'catalog/%s?page=%d'
    );
    $router->addRoute('catalog-section-page',$route);

But this route won't be triggered with '?' symbol in url.

Without '?' (for example, by adding escaped '!' symbol to pattern) everything works as it should. Is there any way to achieve '?' presence in custom defined regex route? Maybe I'm doing something wrong in pattern?

P.S.: Don't offer to use '/' instead of '?', question is exactly about pattern restrictions in Zend_Controller_Router_Route_Regex implementation.

Tim Fountain · Accepted Answer · 2011-02-23 18:01:11Z

2

The ZF routing classes operate on the REQUEST_URI with the query string stripped off, so you may have a hard time get this working in the way you are expecting. However, I believe GET parameters are put into the request object by default, so you shouldn't need to cater for them in your routes. I'd suggest changing your route to remove the query string parts:

$route = new Zend_Controller_Router_Route_Regex(
    'catalog/([-a-z]+)',
    array('controller'=>'catalog','action'=>'list'),
    array(1=>'section'),
    'catalog/%s'
);
$router->addRoute('catalog-section-page',$route);

You should still be able to access the params in your controller as if they had been populated by the routes:

public function listAction()
{
    echo $this->_getParam('page');
}

and you can use the same method to set a default:

public function listAction()
{
    $page = $this->_getParam('page', 1); // defaults to 1 if no page in URL
}

You just may need to sanitise them there (make sure they are numeric).

Edit:

Example of URL helper with this route:

echo $this->url(array('section' => 'foo', 'page' => 2), 'catalog-section-page')

edited Feb 23, 2011 at 18:01

answered Feb 14, 2011 at 15:20

Tim Fountain

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2 Comments

BasTaller Over a year ago

Actually, I'm using Zend Url view helper in my views to build urls later - so question is still unanswered. Considering your code, it would be better to add default value to section parameter, even empty ('section'=>'') - Zend Url view helper will through an error if no section would be passed using this custom route later in views.

Tim Fountain Over a year ago

If section is not required then yes, specify a default. Otherwise it should work as is, as you should always be passing a section to the URL helper if it's required for the routes. I've edited my answer to include an example of a URL helper call for this route, the page param should automatically be added to the query string.

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