Javascript loop ignore array index

Question

I am attempting to loop over product data where each node of data is in its own index of the array. How can I return all "product-name" or "product-url" values regardless of their index?

My code looks like this

var products = res.data.CO;

products.forEach((product, index) => {
    console.log(product);
});

I am able to return each entry but not able to use dot or bracket notation to only bring back one value from each entry. Any help is much appreciated.

Here is my data https://i.sstatic.net/Zn5oL.png

Maybe what you're looking for is the map function?

ErikMD
– ErikMD

2018-04-22 21:45:04 +00:00
Commented Apr 22, 2018 at 21:45 — ErikMD
– ErikMD, Commented Apr 22, 2018 at 21:45

CertainPerformance · Accepted Answer · 2018-04-22 21:49:36Z

1

Use .map to transform one array into another:

const productNames = products.map(product => product['product-name']);

answered Apr 22, 2018 at 21:49

CertainPerformance

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Comments

ug_ · Accepted Answer · 2018-04-22 21:44:55Z

0

You can access values using an array like bracket notation

var products = res.data.CO;

products.forEach((product, index) => {
    console.log(product['product-name']);
});

Or if you just want the product names you could do reduce

s using an array like bracket notation

var products = res.data.CO;

// array of product names
products.map(product => product['product-name']);

answered Apr 22, 2018 at 21:44

ug_

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