How to debug a shell script invoked with "exec"?

Question

Suppose I've got a bash script foo.bash, which uses exec to run another bash script:

exec bar.bash

Now am debugging both foo.bash and bar.bash. I am running foo.bash with bash -x but it does not run bar.bash in debug mode. What should I do to run bar.bash in debug mode too ?

P.P · Accepted Answer · 2018-05-06 13:52:58Z

3

You can also export SHELLOPTS from foo.bash as well to export the shell options.

export SHELLOPTS

answered May 6, 2018 at 13:52

P.P

122k20 gold badges193 silver badges251 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Michael Over a year ago

Can I do it without modifying foo.bash ?

P.P Over a year ago

You can set in -x from the calling shell: $ set -x; export SHELLOPTS; ./foo.bash - this wouldn't require changes to foo.bash. You can also run this from a subshell so that debug output is not printed for everything else: $ (set -x; export SHELLOPTS; ./foo.bash).

John Kugelman · Accepted Answer · 2018-05-06 13:49:28Z

1

Add -x to bar.bash's shebang line:

#!/bin/bash -x

If you don't want to modify bar.bash, change the exec line to:

exec bash -x bar.bash

answered May 6, 2018 at 13:49

John Kugelman

364k70 gold badges555 silver badges600 bronze badges

Collectives™ on Stack Overflow

How to debug a shell script invoked with "exec"?

2 Answers 2

2 Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

2 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related