Ruby count integers in array

Question

Is there a way I can count the number of integers in an array? I have an array whose members come from a-z and 0-9. I want to count the number of integers in said array. I tried:

myarray.count(/\d/)

...but the count method doesn't regex.

a = 'abcdefghijklmnopqrstuvwxyz'.split('')
a << [0,1,2,3,4,5,6,7,8,9]
t = a.sample(10)
p t.count(/\d/)  # show me how many integers in here

count(obj) uses == to count the number of elements equal to obj. So unless you're counting an array of regular expressions your code won't work. Moreover if it did work it still wouldn't count the integers because regex is used with strings. — Sagar Pandya
– Sagar Pandya, Commented May 9, 2018 at 18:15

Zoran · Accepted Answer · 2018-05-09 17:54:06Z

4

The following should return the number of integers present within the array:

['a', 'b', 'c', 1, 2, 3].count { |e| e.is_a? Integer }
# => 3

Since #count can accept a block, we have it check if an element is an Integer, if so it will be counted towards our returned total.

Hope this helps!

edited May 9, 2018 at 17:54

answered May 9, 2018 at 17:47

Zoran

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1 Comment

tadman Over a year ago

Shorter version: ['a', 'b', 'c', 1, 2, 3].grep(Integer).

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