How to match word in regex -python

Question

How to match word in list when i used demo in https://regex101.com/ it's match with \w+ but when I threw in my code the word not detected, So this is my code:

def MultiTrain(self):    
      for fitur in self.fiturs:
            if (fitur[0] == 'F7') or (fitur[0] == 'F8') or (fitur[0] == 'F9') or (fitur[0] == 'F10') or (
                    fitur[0] == 'F13') or (fitur[0] == 'F14') or (fitur[0] == 'F15') or (fitur[0] == 'F16') or (
                    fitur[0] == 'F17') or (fitur[0] == 'F23') or (fitur[0] == 'F24') or (fitur[0] == 'F25') or (
                    fitur[0] == 'F26') or (fitur[0] == 'F27') or (fitur[0] == 'F28') or (fitur[0] == 'F29') or (
                    fitur[0] == 'F30') or (fitur[0] == 'F37') or (fitur[0] == re.findall('\w+', fitur[0])) :
                print fitur

and this is the word i want to match with regex:

F37,0,1,0,1,1,1,0,1,0,2
F7,0,0,0,0,0,0,1,0,1,0
F11,0,0,1,0,0,1,0,0,0,0
angkasa,1,0,1,0,0,0,0,0,0,0
action,0,1,0,0,0,0,0,0,0,0
acu,0,0,0,0,1,0,0,0,0,0
ampun,0,0,0,0,0,0,0,1,0,0

The output of the program is:

    F37,0,1,0,1,1,1,0,1,0,2
    F7,0,0,0,0,0,0,1,0,1,0
    F11,0,0,1,0,0,1,0,0,0,0

but my expectation is:

    F37,0,1,0,1,1,1,0,1,0,2
    F7,0,0,0,0,0,0,1,0,1,0
    F11,0,0,1,0,0,1,0,0,0,0
    angkasa,1,0,1,0,0,0,0,0,0,0
    action,0,1,0,0,0,0,0,0,0,0
    acu,0,0,0,0,1,0,0,0,0,0
    ampun,0,0,0,0,0,0,0,1,0,0

the fitur[0] with word not detected just the F37-F11 How can I fix the regex?

Try using if fitur[0] in ..., it makes for a far more readable code. — Jan
– Jan, Commented May 16, 2018 at 4:21

Rakesh · Accepted Answer · 2018-05-16 04:26:30Z

1

Try.

import re
with open(filename, "r") as infile:
    for fitur in infile.readlines():
        fitur = fitur.split(',')
        if (fitur[0] == 'F7') or (fitur[0] == 'F8') or (fitur[0] == 'F9') or (fitur[0] == 'F10') or (
                fitur[0] == 'F13') or (fitur[0] == 'F14') or (fitur[0] == 'F15') or (fitur[0] == 'F16') or (
                fitur[0] == 'F17') or (fitur[0] == 'F23') or (fitur[0] == 'F24') or (fitur[0] == 'F25') or (
                fitur[0] == 'F26') or (fitur[0] == 'F27') or (fitur[0] == 'F28') or (fitur[0] == 'F29') or (
                fitur[0] == 'F30') or (fitur[0] == 'F37') or (fitur[0] == re.findall('\w+', fitur[0])[0]):
            print fitur

re.findall('\w+', fitur[0]) returns a list. Try using index to access the first element. Ex: re.findall('\w+', fitur[0])[0]

Just a side note. This would be easier to maintain

if (fitur[0] == ['F7', 'F8', 'F9', 'F10', 'F13', 'F14', 'F23', 'F24', 'F25', 'F26', 'F27', 'F28', 'F29', 'F30', 'F37']) or (fitur[0] == re.findall('\w+', fitur[0])[0]):
    print fitur

edited May 16, 2018 at 4:26

answered May 16, 2018 at 4:07

Rakesh

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4 Comments

Fachrul Rozy Saputra R Over a year ago

but in the end of the list i found this \n, ['F37', '0', '1', '0', '1', '1', '1', '0', '1', '0', '2\n'] What is that mean? Is that right? @Rakesh

Fachrul Rozy Saputra R Over a year ago

and why if i change the regex with 'A-Za-z' I got IndexError: list index out of range actually i just want the word. I forgot if regex with \w its match with alphabet and the numeric. But how much with alphabet only @Rakesh

Rakesh Over a year ago

Did you try [A-za-z]+ ?

Fachrul Rozy Saputra R Over a year ago

oh sorry it works, I forgot this thing ) Thank you so much @Rakesh

Axecalever · Accepted Answer · 2018-05-16 04:10:13Z

0

It is because re.findall('\w+',fitur[0]) is returning a list ['action'] try re.findall('\w+',fitur[0])[0] instead

answered May 16, 2018 at 4:10

Axecalever

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