replace the first occurrence of a string element in list [duplicate]

Question

I need to change the first occurrence of a 1 into a 0 for each element of a string in list, but it changes everything:

a, b = input().split()
a = int(a)
d=[]
for x in range(1,a+1):
    globals()['side%s' % x] = input("Enter something: ")
    d.append(globals()['side%s' % x])

d = [s.replace('1', '0') for s in d]


print(d)

Example:

4 1 // 4 number of inputs, 1 - number of possible changes to string

0101
0010
0100
1000

need to be

If I understand correctly, you only want to replace the first occurence of a 1 with 0 and leave the other occurences unchanged? — Aran-Fey
– Aran-Fey, Commented May 21, 2018 at 6:27
@Bad.coder This is a duplicate of stackoverflow.com/questions/4628618/…. Answer: replace() takes an optional third argument, the maximum number of times to replace. For example, replace('1', '0', 1) will perform the replacement on only the first instance — daveruinseverything
– daveruinseverything, Commented May 21, 2018 at 6:32

harshil9968 · Accepted Answer · 2018-05-21 06:36:45Z

1

since you want x number of occurrence to be replaced, the replace function offers this string.replace(s, old, new[, maxreplace]), you might want to pass on b which is the maxreplace as the third parameter.

a, b = input().split()
a = int(a)
d=[]
for x in range(1,a+1):
    globals()['side%s' % x] = input("Enter something: ")
    d.append(globals()['side%s' % x])

d = [s.replace('1', '0', int(b)) for s in d] # maxreplace will be b only


print(d)

edited May 21, 2018 at 6:36

answered May 21, 2018 at 6:31

harshil9968

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