Create a variable/DataFrame that gets its name from a parameter of a function

Question

I have tried searching the forums, but couldn't really find one for the problem I am facing.
I am trying to create a dataframe within a function. However the name of the dataframe is something I want to dynamically create based on a parameter value that is passed to the function.

Am not sure how I can do this in a quick way. Can you please advise.

Eg:

def Upload(file, ABC):
    df_ABC = pd.read.......
    return df_ABC


def Upload(file, NYK):
    df_NYK = pd.read.......
    return df_NYK

Possible duplicate of Get the name of a Pandas DataFrame [Python] — Georgy
– Georgy, Commented May 21, 2018 at 9:59
So you want to dynamically create variables from these functions? — zipa
– zipa, Commented May 21, 2018 at 10:00
@zipa : Yes, the parameter value should be dynamically appended to a variable in order to form a unique variable name/string — asimo
– asimo, Commented May 21, 2018 at 10:04
What's wrong with df.name attribute? What are you trying to achieve anyway? — Georgy
– Georgy, Commented May 21, 2018 at 10:05

Mihai Alexandru-Ionut · Accepted Answer · 2018-05-21 10:14:36Z

1

I want to dynamically create based on a parameter value that is passed to the function.

You can use locals.

locals()['df_'+ ABC] = pd.read....

But it's not recommended to do this. Use a dictionary instead.

my_dict = {}
my_dict['df_' + ABC] = pd.read.......

When you want to return value the dataframe just use bracket notation.

return my_dict['df_' + ABC]

edited May 21, 2018 at 10:14

answered May 21, 2018 at 9:59

Mihai Alexandru-Ionut

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3 Comments

asimo Over a year ago

@ Mihai Alexandru-lonut : Can you please share a template how the dictionary can be used for this..

asimo Over a year ago

And how would the return statement look like. return df_ ?

Mihai Alexandru-Ionut Over a year ago

@asimo, return my_dict['df_' + ABC]

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