jQuery recursive function error

Question

I am trying to make the following recursive function work but keep receiving an error (following code):

var checkStatus = function(jobID) {
        $.ajax({
            type: 'post',
            url: '/admin/process/check-encode-status.php',
            data: {jobID: jobID},
            success: function(data) {
                if (data == 'processing') {
                checkStatus(jobID).delay(2000);
                } else {
                    $("#videoOutput").html(data);
                }
            }
        });
     };

The error I am receiving is: checkStatus(jobID) is undefined

Everything seems to be working as it should, Firebug is just throwing this warning. The function is repeating itself, posting the jobID and receiving "processing" from the PHP script.

I had a similar script that I was using that used setTimeout() to be recursive but I could not figure out how to pass the jobID along with calling the function (errors).

Any ideas? Thanks!

user113716 · Accepted Answer · 2011-02-18 20:09:30Z

3

Just remove the .delay() and you'll get rid of the error. You should use setTimeout instead.

var checkStatus = function (jobID) {
    $.ajax({
        type: 'post',
        url: '/admin/process/check-encode-status.php',
        data: {
            jobID: jobID
        },
        success: function (data) {
            if (data == 'processing') {
                setTimeout(function() { // <-- send an anonymous function
                    checkStatus(jobID); // <--    that calls checkStatus
                }, 2000);
            } else {
                $("#videoOutput").html(data);
            }
        }
    });
};

This is because checkStatus() doesn't return anything explicitly, so you're trying to call .delay() on undefined.

answered Feb 18, 2011 at 20:09

user113716

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1 Comment

NightMICU Over a year ago

Works great, thanks! Kind of dumb of me to use .delay() for that, of course that wouldn't work. Thanks again for the help

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