linux shell variable to aws command error

Question

I have spent an embarrassingly long time trying to solve this riddle.

I have a shell variable called API_ID which I parsed from json using jq

ludo$ echo $API_ID
> "ucjj72orp1"

Why is it that when I copy paste it like this it works fine:

aws apigateway get-resources --rest-api-id "ucjj72orp1"

and like this I get an error:

aws apigateway get-resources --rest-api-id $API_ID
An error occurred (NotFoundException) when calling the GetResources operation: Invalid REST API identifier specified 420257254224:"ucjj72orp1"

Did you use option -r in your jq command? If not, the variable $API_ID might contain double quote, that possibly makes an invalid aws id. — oliv
– oliv, Commented May 22, 2018 at 9:45
That worked! But how is it that when I input it manually with double quotes it works anyway? — Ludo
– Ludo, Commented May 22, 2018 at 9:49

oliv · Accepted Answer · 2018-05-22 09:55:02Z

1

You need to use -r option in your jq command. This allows to get raw data without double quote.

If you set myvar=$(jq '...'), the variable will be set to a shell string including surrounding double quote.

If you copy/paste the string in an inline shell command, the shell interprets the double quote as string separator, and therefore it works.

answered May 22, 2018 at 9:55

oliv

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