Reading from binary as float(4 bytes per number) to csv file

Question

I would like to read from a binary as float values and write them to a csv file, which almost works with the code below. The thing is struct.unpack is writing the float value like:

(number,)

and I would like to write it without the paranteses,().

Is there a better way to get the values as a float instead of using unpack or what do you suggest?

count = 0
output_file = open(r"C:\Users\heltbork\Desktop\binTocsvDirect\00000006.txt", "w")

with open(r"C:\Users\heltbork\Desktop\binTocsvDirect\00000006.bin", "rb") as f:
    while True:
        byte = f.read(4)
        if not byte:
            break
        output_file.write(str(unpack('f', byte)))
        count = count + 1
        if count == 6:
            count = 0
            output_file.write("\n")

Reut Sharabani · Accepted Answer · 2018-05-22 12:51:23Z

1

Its just a string form of a tuple.

unpack(...)

Gives back a tuple.This is stated in the docs:

... The result is a tuple even if it contains exactly one item.

If you want the first element:

first = unpack('f', byte)[0]

In your code, use:

output_file.write(str(unpack('f', byte)[0]))

Tip: Use the csv module.

answered May 22, 2018 at 12:51

Reut Sharabani

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