Array_push to reference variable causing syntax errors

Question

Been quite some time since I did PHP; but, something that I believe used to work doesn't seem to be working PHP 7

$list = array ();
while ( ($data = fgetcsv($handle) ) !== FALSE ) {
  $row = array ();
  $row[0] = 1;
  array_push(&$list,$row);
}

This seems to fail due to "Parse error: syntax error, unexpected '&'" however if I take the & off the $list array won't have the $row array inside of it due to scope. Has this changed in PHP 7 on how to handle this?

try changing !== to != . You don't need the extra '=' for a Boolean comparison. — briskovich
– briskovich, Commented May 24, 2018 at 22:04
There shouldn't be a scope issue inside the example probably something else. — Danny
– Danny, Commented May 24, 2018 at 22:04
There's no need for &. Once you create a reference variable you just use it normally. — Barmar
– Barmar, Commented May 24, 2018 at 22:07
Call-time pass by reference has been removed in PHP 5.4 (iirc). Sounds like a really long time. — jh1711
– jh1711, Commented May 24, 2018 at 22:10

Barmar · Accepted Answer · 2018-05-24 22:10:45Z

3

If you're trying to push a reference to $row, it should be:

$list[] = &$row;

Reference syntax can't be used in function calls, only assignments. Assigning to an array followed by [] is equivalent to array_push().

answered May 24, 2018 at 22:10

Barmar

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