Parsing data from a REST URL

Question

I have a url which looks like this https://test.sample.com/product/<product_Id>/subproduct/<sub_product_id>

I'm trying to get the <product_id> and <sub_product_id> from this in the best clean way possible.

What I've tried is to do a String split, loop through each item and get the items after "product" and "subproduct".

Is this the only way to do this ? Or rather the best possible way ?

@MeetTitan Where does the OP mention JSON anywhere? I'm not seeing it. — Tim Biegeleisen
– Tim Biegeleisen, Commented May 25, 2018 at 10:56
Thanks @sudha but I had already checked that question and it doesn't solve my purpose (because of multiple variables in the path). It's a good approach to isolate the path from the base URl and other query params — RmK
– RmK, Commented May 25, 2018 at 14:01

Tim Biegeleisen · Accepted Answer · 2018-05-25 10:55:09Z

5

Splitting the url string is one option, but we can try using String#replaceAll for a regex based one liner approach:

String url = "https://test.sample.com/product/<product_Id>/subproduct/<sub_product_id>";
System.out.println(url.replaceAll(".*/product/(.*?)/.*$", "$1"));
System.out.println(url.replaceAll(".*/subproduct/(.*?)$", "$1"));

<product_Id>
<sub_product_id>

Demo

answered May 25, 2018 at 10:55

Tim Biegeleisen

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3 Comments

RmK Over a year ago

Went ahead with this answer because this insulates the app's code from any changes in the URl structure as long as the IDs are preceded by the key.

Tim Biegeleisen Over a year ago

@RmK I don't know what exactly you have in mind by "delimiters," but if you're referring to / then no, it doesn't require any special handling. Forward slash is not a metacharacter.

RmK Over a year ago

Thanks again ! Sorry I removed the comment right after posting it when it hit me :)

Majva · Accepted Answer · 2023-07-05 11:29:47Z

1

You can use Uri class in android.net.Uri

  Uri uri = Uri.parse("https://test.sample.com/product/4/subproduct/8");
    List list =  uri.getPathSegments();
    Log.d("productid",list.get(1).toString());
    Log.d("subproductid",list.get(3).toString());

edited Jul 5, 2023 at 11:29

answered May 25, 2018 at 11:22

Majva

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2 Comments

Tim Biegeleisen Over a year ago

The only drawback of this approach is that it assumes fixed positions for the two components.

RmK Over a year ago

Thanks Majid. Although I agree with @TimBiegeleisen here because this is going to be used in an app and I wouldn't want do do a new release just because the URL structure got changed.

Gunnar Dag · Accepted Answer · 2018-05-25 11:31:35Z

0

This works if you know the url will always be formatted the same. String url = "https://test.sample.com/product/asdf/subproduct/qwerty"; String[] urlArray = url.split("/"); // check may be here if the array is at least more than 7 or whatever length you require. String product = urlArray[4]; String subproduct = urlArray[6];

answered May 25, 2018 at 11:31

Gunnar Dag

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