Passing pointer into Class method [duplicate]

Question

I am learning C++ and have a problem with pointers. I want to pass a pointer into my method and assign it a new value. But my pointer is 0 after the method was called. What am I doing wrong? Thanks

#include <iostream>

using namespace std;

class MyObject
{
    public:
        bool search(int* a) 
        {
            int* test = new int(23);
            a = test;
            return true;
        }
};


MyObject* obj;

void search()
{
    int* test = NULL;
    obj->search(test);
    cout << test << endl;
}

int main(int argc, char *argv[])
{
    obj = new MyObject();
    search();
}

@StaticBeagle None of the answers there seem to show how to pass a reference to a pointer. I'm not sure it's a good duplicate. — Barmar
– Barmar, Commented Jun 1, 2018 at 5:11
Unrelated: Consider making obj an automatic variable inside main and passing it into search as a parameter. Global variables are not strictly bad, but they can make your life harder than it needs to be as your programs grow more complex.. — user4581301
– user4581301, Commented Jun 1, 2018 at 5:23
@rwp that code is only C if agajvery is using some really impressive macros. — user4581301
– user4581301, Commented Jun 1, 2018 at 6:14

Longarmx · Accepted Answer · 2018-06-01 05:16:19Z

3

You need to pass the pointer by reference.

bool search(int*& a)

Without this, the pointer is passed by value, and you are only assigning a copy of what you passed. To assign the actual object/variable you pass, you need to pass the pointer by reference.

For further reading: What's the difference between passing by reference vs. passing by value?

edited Jun 1, 2018 at 5:16

answered Jun 1, 2018 at 5:09

Longarmx

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3 Comments

Algirdas Preidžius Over a year ago

Where is the explanation of why, and what's the difference, between pass-by-reference, and pass-by-value?

Longarmx Over a year ago

Added explanation

user4581301 Over a year ago

Perfect. Succinct and hits on all the key terms an asker needs to perform research for more information should they want it.

tttapa · Accepted Answer · 2018-06-01 05:10:44Z

0

a is a local variable, if you set its value during the search method execution, it won't have any effect on the test variable in the free search function, because a is just a copy of test.

You should pass a by reference:

bool search(int *&a) { 
    int* test = new int(23);
    a = test; 
    return true; 
}

answered Jun 1, 2018 at 5:10

tttapa

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Comments

Destructor · Accepted Answer · 2018-06-01 07:01:51Z

0

The pointer was passed by value instead of reference. Which means the local variable test's value was not changed.

Instead do bool search(int*& a)

This will pass the reference to the method, which will update the local variable in the calling function.

answered Jun 1, 2018 at 7:01

Destructor

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