multidimensional array filtering javascript [closed]

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I have a multidimensional array

[
  ["apple" , 50],
  ["pie", 45]
  ["steak", 78]
]

I have one another array

["apple","pie"]

How can I filter first array into this result:

[
    ["apple" , 50],
    ["pie", 45]
]

function sorting(value){ 
  var sorted = new Array(); 
  for(var i =0; i <Object.keys(inputArray); i++)
  { 
    if (inputArray[i].keys === value)
    { 
      sorted.push(inputArray[i]); 
    } 
  } 
  return sorted; 
}

this may be your solutionhttps://stackoverflow.com/questions/9206914/how-to-filter-multidimensional-javascript-array — byeke
– byeke, Commented Jun 5, 2018 at 22:14
Please note that Stackoverflow is not a free code writing service. The objective is for you to show what you have attemted to solve your issue and people help you with your code when it doesn't work as expected — charlietfl
– charlietfl, Commented Jun 5, 2018 at 22:14
function sorting(value){ var sorted = new Array(); for(var i =0; i <Object.keys(inputArray); i++){ if (inputArray[i].keys === value){ sorted.push(inputArray[i]); } } return sorted; } — Rauf
– Rauf, Commented Jun 5, 2018 at 22:15

Pang · Accepted Answer · 2018-06-07 01:38:50Z

1

Try this:

var firstArray = [
  ["apple" , 50],
  ["pie", 45],
  ["steak", 78]
];
var secondArray = ["apple","pie"];

var thirdArray = [];

for (var i = 0; i < firstArray.length; i++) {
  if (secondArray.includes(firstArray[i][0])) {
    thirdArray.push(firstArray[i]);
  }
}
console.log(thirdArray);

This is of course used if you don't want to use the .filter method.

edited Jun 7, 2018 at 1:38

Pang

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answered Jun 5, 2018 at 22:18

Sheshank S.

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Comments

Taki · Accepted Answer · 2018-06-05 22:45:18Z

0

you can use Array.filter() and Array.includes()

const arr1 = [
  ["apple", 50],
  ["pie", 45],
  ["steak", 78]
]

const arr2 = ["apple", "pie"]

const result = arr1.filter(e => arr2.includes(e[0]))

console.log(JSON.stringify(result))

answered Jun 5, 2018 at 22:45

Taki

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2 Comments

Rauf Over a year ago

why you stringify the end result?

Taki Over a year ago

Just for display purposes , not necessary

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