Save JSON String in Object

Question

i want to save a JSON-String into an existing Object in Swift:

This is my Object:

struct Benutzer : Decodable, Encodable{
let userRights: [String]
}

This is my String:

str = "{"user_rights":["terminal_create"]}"

That is my Code:

do { let data1 = str.data(using: String.Encoding.utf8, allowLossyConversion: false)

let User = try JSONDecoder().decode(Benutzer.self, from: data1 as Data)

print(User)

 }catch{
       print("Error serializing!")
  }

With this code, "Error serializing!" shows up every time. Do you guys know whats up? Sorry, I am still a complete beginner. Sorry for not formatting the question I don't quite get it :( I get this String from another JSON request: I get this as an answer, the JSON data string that I want to decode is part of that answer:

Answer(api_version: 1, result: "login", success: true, token: "da39a3ee5e6b4b0d3255bfef95601890afd80709", data: "{\"user_rights\":[\"terminal_create\"]}")

This is a Answer-Object:

struct Answer: Decodable, Encodable{

    let api_version: Int
    let result: String
    let success: Bool
    let token: String
    let data: String

}

Maybe you know another way how to extract that Data into a Benutzer Object. I would be really thankful, thanks a lot guys!

Show us the exact value of str. And print the error in your catch: print("Error serializing: \(error)"). — rmaddy
– rmaddy, Commented Jun 7, 2018 at 20:50
Error serializing: keyNotFound(CodingKeys(stringValue: "userRights", intValue: nil), Swift.DecodingError.Context(codingPath: [], debugDescription: "No value associated with key CodingKeys(stringValue: \"userRights\", intValue: nil) (\"userRights\").", underlyingError: nil)) — Raphael Schmidt
– Raphael Schmidt, Commented Jun 7, 2018 at 20:55

Abdelahad Darwish · Accepted Answer · 2018-06-07 20:56:29Z

1

your coding key not similar to what in your string userRights , user_rights

so do like that:

struct Benutzer: Codable {
        let userRights: [String]

        enum CodingKeys: String, CodingKey {
            case userRights = "user_rights"
        }
    }

answered Jun 7, 2018 at 20:56

Abdelahad Darwish

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1 Comment

Raphael Schmidt Over a year ago

Thank you so much I completely overlooked that! Now it works. Thanks!

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