c function call using a function arguments

Question

void TraverseList(const List *l , void (*Visit)(ListEntry)) { // }

I confused about the above function call within the argument of a function,how it is working?

I suggest you find some books to read, or at least some tutorials about function pointers. — Some programmer dude
– Some programmer dude, Commented Jun 11, 2018 at 5:50
It is not a function call but an argument of type void(*)(ListEntry) — Killzone Kid
– Killzone Kid, Commented Jun 11, 2018 at 5:56
You can always check cdecl.org - void (*Visit)(ListEntry) ==> declare Visit as pointer to function (ListEntry) returning void — CIsForCookies
– CIsForCookies, Commented Jun 11, 2018 at 6:12

Lundin · Accepted Answer · 2018-06-11 06:30:45Z

2

Visit is a function pointer parameter passed to the TraverseList function. It should point to a function with the format

void func (ListEntry);

Likely, TraverseList will call the passed function for every item in the list.

answered Jun 11, 2018 at 6:30

Lundin

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